koda10
Graph each system of inequalities. Then use your graph to identify a solution to the system.
x > -2
y 2x + 7
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koda10
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|dw:1355995233844:dw|
koda10
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|dw:1355995242269:dw|
hartnn
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whats the 2nd equation ?
koda10
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|dw:1355995347577:dw|
hartnn
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just type instead of drawing :P
koda10
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|dw:1355995365260:dw|
koda10
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koda10
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koda10
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hartnn
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x>-2|dw:1355995605154:dw|
koda10
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(-1, 6)
koda10
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so
koda10
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(-1, 6)
hartnn
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what is -1,6 ??
you would have a region as solution, right ? not a point....
koda10
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-(3, -1)
koda10
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(-3, -1)
Hr.Tboy
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0
|dw:1355995869420:dw|
hartnn
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thats looks so shabby :P
koda10
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(1, 11)
hartnn
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do u have choices/options ?
koda10
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(-1, 6)
(1, 11)
(-1, 4)
(-3, -1)
hartnn
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ok, x>-2, so D is out
koda10
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(1, 11)
koda10
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|dw:1355996246427:dw|
hartnn
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wait, 11<2+7
this is false. so not 1,11
koda10
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Graph each system of inequalities. Then use your graph to identify a solution to the system.
2x - 5y > 0
x - 4y > -8
(Points : 1)
(28, 9)
(28, 16)
(32, 10)
(32, 8)
koda10
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(-1, 4)
hartnn
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4< -2+7 is true, so yes
koda10
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Graph each system of inequalities. Then use your graph to identify a solution to the system.
2x - 5y > 0
x- 4y >- 8
(Points : 1)
(28, 9)
(28, 16)
(32, 10)
(32, 8)
koda10
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(32, 8)
hartnn
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yes.
hartnn
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can't open
koda10
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Select the system of linear inequalities whose solution is graphed.
(Points : 1)
y > 3x - 1; x + 3y < 6
y 3x- 1; x + 3y 6
y < 3x - 1; x + 3y > 6
y > 3x - 1; x + 3y 6
hartnn
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that links doesn't work for me
koda10
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y > 3x - 1; x + 3y < 6
y< 3x- 1; x + 3y > 6
y < 3x - 1; x + 3y > 6
y > 3x - 1; x + 3y <6
hartnn
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can't open that link so can't help
koda10
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koda10
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koda10
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koda10
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