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@ashwinjohn3 what would be the answer in your opinion?

ur answer will b 148.48 m

can i explain my work

ok use the equation.......
Diplacement @ nth second=u+ a(2n-1)/2

no

i wanna use the equation\[h=ut+ \frac{ 1 }{ 2 } g t ^{2}\]

for full height u=0

and my equation become
\[h=0+\frac{ 1 }{ 2 } g t ^{2}\]

\[h=\frac{ 1 }{ 2 } \times 10 \times t ^{2}=5 \times t ^{2}\]

its my 1st equation

now i wanna write another equation for 1st 2/3 h height

\[\frac{ 2 }{ 3 }h=ut+\frac{ 1 }{ 2 } \times g t ^{2}=\frac{ 1 }{ 2 } \times 10 \times (t-1)^{2}\]

now u hv to solve these 2 equation to get time t and then u will get the height h