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anonymous
 3 years ago
A rock dropped from a cliff covers onethird of its total distance to the ground in the last second of its fall. Air resistance is negligible. How high is the cliff?
anonymous
 3 years ago
A rock dropped from a cliff covers onethird of its total distance to the ground in the last second of its fall. Air resistance is negligible. How high is the cliff?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@experimentX @shubhamsrg @JFraser

JFraser
 3 years ago
Best ResponseYou've already chosen the best response.0this is already in the physics group

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can u Check My answer i got h = 148.48 m

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1s = 1/2 gt^2  v = 0 + g(t1) now u = v then, 1/3 s = v(1) + 1/2 g(1)^2 s = 1/2 gt^2  from these two solve or 's' and 't' rest should be okay

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.0nicely explained @experimentX

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok....i Did by this way: h = 1/2 g t^2 Dn = u + a/2 (2n1) h/3 = a/2(2t1).....?

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2in the formula you used @Yahoo! 'n' is the nth second, in your case, n= t1 .. you already know h= 1/2 gt^2 also h/3 =g/2 (2t 3) taking g=10, i get h=45..someone please confirm ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But why Do we take t1

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2last second right ? after t seconds are complete , the object doesnt travel further..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I am Silly....u r correct...i got it now....

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2i may be wrong in logic though.. let someone else make any correction if its there..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think ur Logic is Correct...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But Lets Confirm..as u told..@sauravshakya

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2maybe not tagged correctly..allow me @sauravshakya

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2you got 148 right? by another plausible method, i am also getting 148, so that should be right,,my logic is thus, flawed//hmm..

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.2here is what i did,, we h = 1/2 g t1 ^2 ....(1) where t1 is total time taken . let t2 be time before it comes to last second of the journey, thus t1  t2 =1 => t2 = t1 1....(2) we know h h/3 = 1/2 g t2 ^2 2h/3 = 1/2 g t2 ^2 ...(3) using 1,2,and 3 eqns, we can solve for h, t1 and t2 .. by taking g=10, i approximately get h=148.4 something.. which should be the ans.. unless ofcorse,,there is some flaw in this also! :

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This one looks correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But This one Luks Similar to 1st One @shubhamsrg
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