anonymous
  • anonymous
a wedding planner must select from 4 possible venues for an actual wedding, and 3 venues for the reception. how many arrangements are possible ?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
12 assuming there has to be a reception, 16 if no reception is an option
anonymous
  • anonymous
how do you come up with that ?
anonymous
  • anonymous
i came up with 24

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anonymous
  • anonymous
ok so start by thinking of the possibilities: wedding venue 1 and reception venue 1 wedding venue 1 and reception venue 2 wedding venue 1 and reception venue 3 that's 3 solutions for one given wedding venues and repeat for the other 3 wedding venues that multiplies this result by 4: 3x4 = 12 we have covered all possibilities
anonymous
  • anonymous
i did it by doing 4!/4-3!
anonymous
  • anonymous
If there is a rule that justifies what you are doing there then great! but its always good to be able to think it through logically if all else fails!

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