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mexx4u2nv
Group Title
For the same kinetic energy, the momentum shall be maximum for which one of these:
1. Electron
2. Alpha particles
3. Neutron
4. Deuteron
5. Proton
6. Gamma particles
 one year ago
 one year ago
mexx4u2nv Group Title
For the same kinetic energy, the momentum shall be maximum for which one of these: 1. Electron 2. Alpha particles 3. Neutron 4. Deuteron 5. Proton 6. Gamma particles
 one year ago
 one year ago

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MyLifeIsChemical Group TitleBest ResponseYou've already chosen the best response.1
Alpha Particles, as p=m*v and the mass of an alpha particle is greater than the other options
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
K=mv^2/2 this can be written as : K=m^2*v^2/2m which can be written in terms of momentum as: K=p^2/2m Rearranging the terms : p=sqrt(2Km) For given K, the larger the mass of the particle the greater will be its p Hence "alpha particle" will have greater momentum. NOTE: However the converse is not true For given momentum the lighter particle will have greater Kinetic energy as can be seen from the formula: K=p^2/2m This is contrary to what one may expect.
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.2
Kinetic energy is given by \[KE = \frac{ 1 }{ 2 } m v^2\] rearrange to to find v, since KE is the same for all:\[v = \sqrt{\frac{ 2 \times KE }{m}}\]and insert this into the formula for momentum, p = mv \[\rho = m v = m \sqrt{\frac{ 2 \times KE }{m}}\] and square the m and bring it under the square root sign, cancel off an m, to get: \[\rho = \sqrt{2 \times KE \times m}\] Since 2*KE is the same for all the particles, momentum is proportional to the square root of mass  the larger the mass of the particle, the higher the momentum.
 one year ago
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