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anonymous
 3 years ago
Formulas for 6?
(I have all the other formulas, for 1 2 3 4 and 5, in case anyone needs)
anonymous
 3 years ago
Formulas for 6? (I have all the other formulas, for 1 2 3 4 and 5, in case anyone needs)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have the following values :V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Q2 P3 formula benzo is correct. How are you inputing your values? Give them to me and let me compute, then we compare.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did it give 2.60944 to you?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ Jone133, we have the same values. a=0.1, b=0.1, c= 7.942. still having problems with d.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@kidarth what about 1.69315?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i Checked it its right given your values

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got mine right in 2nd try

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i said i checked your answer by changing my values to yours just after i completed my analysis so i think the anser 1.69 is right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@kidarth i said i checked your answer by changing my values to yours just after i completed my analysis so i think the anser 1.69 is right Happy 100%

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0gooood I think i need government authorised documents and signatures to make you believe me i didnt use any formula but instead used transient analysis if you think my answer is right, use it ,rest is your choice

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Q2: q2 p1: Vs as vin<vt p2: v0 = vskr(e^((vinvt)/vn)1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: kre^((vinvt)/vn) p6: kr(vinvt) vs=4 r =1k k = 1 VT = 1 Vn = 1 vs=4.5 r = 1k k =1mA vt=1 vn=1 1: 4.5 vin=0.5 2: 2.7818 vin=2 3: 2.1786 vo=vs/2 4: 3.1213 vo=vs/2 mosfet 5: 2.7182 vin=2 6: 1 vin=2 mosfet

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0formula for question 1?
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