Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

A small spaceship whose mass is 1.5x10^3 kg (include-ing an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a 10 kW laser beam, what speed will the ship attain in 1.0 day because of the momentum carried away by the beam?

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

can u tell me the result option
The answer is 1.9 mm/s.
ok

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

i m trying
i got the result velocity is 759 m/s
should i explain my procedure
Yes, show me the work you did.
ok i m showing
let m= mass p=power t=time F=force s= distance
v=final velocity
a= acceleration
Now\[P=\frac{ W }{ t }=\frac{ Fs }{ t }=F\frac{ s }{ t }=Fv\]
What is the distance, s?
\[or, 10000=Fv \]
we know work= force* displacement or distaance
or, \[F=10000/v\]
now we know \[F=ma\]
or, \[F=1500a\]
or, \[10000/v=1500a\]
r u getting my work
or, \[a=10000/1500v\]
now another law of motion is \[v=u+at=0+at=at=(10000/1500v) \times 24 \times 60 \times 60\]
now solve it for v
Never mind. I found a formula for this problem, but thanks for the help.

Not the answer you are looking for?

Search for more explanations.

Ask your own question