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Idealist
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A small spaceship whose mass is 1.5x10^3 kg (includeing an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a 10 kW laser beam, what speed will the ship attain in 1.0 day because of the momentum carried away by the beam?
 one year ago
 one year ago
Idealist Group Title
A small spaceship whose mass is 1.5x10^3 kg (includeing an astronaut) is drifting in outer space with negligible gravitational forces acting on it. If the astronaut turns on a 10 kW laser beam, what speed will the ship attain in 1.0 day because of the momentum carried away by the beam?
 one year ago
 one year ago

This Question is Closed

shamim Group TitleBest ResponseYou've already chosen the best response.1
can u tell me the result option
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.0
The answer is 1.9 mm/s.
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
i got the result velocity is 759 m/s
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
should i explain my procedure
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.0
Yes, show me the work you did.
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
ok i m showing
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
let m= mass p=power t=time F=force s= distance
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
v=final velocity
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
a= acceleration
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
Now\[P=\frac{ W }{ t }=\frac{ Fs }{ t }=F\frac{ s }{ t }=Fv\]
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.0
What is the distance, s?
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
\[or, 10000=Fv \]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
we know work= force* displacement or distaance
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
or, \[F=10000/v\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
now we know \[F=ma\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
or, \[F=1500a\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
or, \[10000/v=1500a\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
r u getting my work
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
or, \[a=10000/1500v\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
now another law of motion is \[v=u+at=0+at=at=(10000/1500v) \times 24 \times 60 \times 60\]
 one year ago

shamim Group TitleBest ResponseYou've already chosen the best response.1
now solve it for v
 one year ago

Idealist Group TitleBest ResponseYou've already chosen the best response.0
Never mind. I found a formula for this problem, but thanks for the help.
 one year ago
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