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## suneja Group Title P= a - bN {(p-t)/wc}^1/1-z wer z>1 differentiate tis expression wrt ' t' one year ago one year ago

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1. RadEn Group Title

too many variables there :)

2. suneja Group Title

dat the prob!! can u solve tis its profit maximizing level of output inclusive of tax...had to be weird..

3. suneja Group Title

|dw:1356073901037:dw|

4. Kainui Group Title

$P=a-bN (\frac{ p-t }{ wc })^{(\frac{ 1 }{ 1-z })}$ differentiate with respect to t when z>1 right? I think we can do this.

5. suneja Group Title

@Kainui plz do

6. Kainui Group Title

It seems confusing but try to take it one bit at a time. Remember that all of these are essentially constants like the number 5, 23, or whatever. Give it your best shot and show me what you get.

7. Kainui Group Title

You should try splitting up the fraction within so that it's more easy to look at. I suggest trying to isolate "t" because everything else is just a constant and will lead to confusion.

8. suneja Group Title

i've tried n ... m getting tha same crap .. can u show me ur steps plz!!

9. shubhamsrg Group Title

i have never knows about taxes much,,just confirming.. we have to find DP/dt right ? given t is the only variable and all others are constants ?

10. shubhamsrg Group Title

known*

11. suneja Group Title

@shubhamsrg dats rite u dont need to knw abt taxes or nething its jst a typical expression!

12. Kainui Group Title

Alright I'll write out some steps because this is particularly confusing, give me a moment to make it clear in my description.

13. shubhamsrg Group Title

i see.. then check this please : |dw:1356074934050:dw|

14. suneja Group Title

dats exactly wat m getting but the soln given has a numerator and denomenator

15. shubhamsrg Group Title

whats the solution ?

16. Kainui Group Title

$P=a-bN( \frac{ p-t }{ wc })^{\frac{ 1 }{ 1-z }}$ Now since everything else is constant, separate out the t into its own term to make it clear what we're differentiating: $P=a-bN( \frac{ p }{ wc }-\frac{ t }{ wc })^{\frac{ 1 }{ 1-z }}$ Now from here you can take the derivative more simply by using the chain rule. You'll see that a goes to 0, since the derivative of any constant is 0. We're doing this with respect to t. Now if you use the chain rule on the second part, let's consider a simpler looking expression: $5(3-2t^2)^7$ this looks exactly like the second part of the problem, yes? When we use the chain rule we take the derivative of the outside and multiply it by the derivative of the inside like this: $35(3-2t^2)^6* (-4t)$ You must do the same thing here.

17. Kainui Group Title

That looks like what I got too, I even simplified it down to the same exact thing as you.

18. suneja Group Title

hey m sorry but there is minor change in ques... instead of w its z m sorry guy n lemme post dat ans for

19. Kainui Group Title

Not much will change, suneja since both are constants.

20. shubhamsrg Group Title

yep..exactly!

21. Kainui Group Title

Don't get caught up in looking at them as letters. Do the exact same thing you would do as if they were just any other constant number.

22. suneja Group Title

|dw:1356075429814:dw|

23. suneja Group Title

@shubhamsrg @Kainui this is the ans .... i got the same ans as u guys now can u guys show me how did they get tis one and mind u its NOT WRONG ANS as its has economic interpretation attached

24. Kainui Group Title

Hmm well what's the economic interpretation? I suppose the only difference is just some algebraic manipulation?

25. suneja Group Title

here denum is = 1+numerator so dp/dt <1

26. Kainui Group Title

So wait, you have to get it in the same form as this? I'm not sure I understand what you want here.

27. suneja Group Title

@Kainui jst dP/dt dat et

28. Kainui Group Title

I think you got it.

29. suneja Group Title

guys thanks for ur tym n effort... but i guess i'l hav to figure it out maslf!!

30. Kainui Group Title

Good luck!