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Jadelynn

  • 3 years ago

Solve the exponential equation 9^2x = 27

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  1. Yahoo!
    • 3 years ago
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    9 = 3^2 9^2x = 3^4x 27 = 3^3 Compare 4x = 3 x = 3/4

  2. agent0smith
    • 3 years ago
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    We have\[9^{2x}=27\] \[(3^{2})^{2x}=3^{3}\] \[3^{4x} = 3^{3}\] so 4x = 3

  3. Jadelynn
    • 3 years ago
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    Can I get an explanation on how you did that?

  4. ShikhaDessai
    • 3 years ago
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    9 is nothing but 3^2 and 27 is 3^3 so we need to make the base common to make it possible to solve for 'x'.... so............... 3^2(2x) = 3^3 therefore 3^4x = 3^3 since the base is the same, the exponents are equal;( since it is an equation and the left hand side is equal to the right hand side). so, 4x = 3 hence x = 3/4

  5. ShikhaDessai
    • 3 years ago
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    did u understand my explanation @Jadelynn ? because if u didnt i can explain again

  6. Jadelynn
    • 3 years ago
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    Yes I did. Thank you

  7. agent0smith
    • 3 years ago
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    Good explanation, @ShikhaDessai

  8. ShikhaDessai
    • 3 years ago
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    thank you so much!!!

  9. 66
    • 2 years ago
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    how do you solve the equation 9^2x = 27

  10. 66
    • 2 years ago
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    using exponential and logarithmic form

  11. agent0smith
    • 2 years ago
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    @66 maybe post a new question... this one is four months old.

  12. 66
    • 2 years ago
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    not mine please help if posible

  13. agent0smith
    • 2 years ago
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    "how do you solve the equation 9^2x = 27" Or... just read above... your question is already answered above and explained twice...

  14. 66
    • 2 years ago
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    kk thx a lot

  15. agent0smith
    • 2 years ago
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    If you need to do it with logarithms, then take logarithms of both sides of 9^2x = 27

  16. 66
    • 2 years ago
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    how do you do that and its not solved above

  17. 66
    • 2 years ago
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    can you please help if not then i will google search it , but thanks for your help anyway

  18. 66
    • 2 years ago
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    ??????????????????????????

  19. 66
    • 2 years ago
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    does anyone know how to solve for the equation 9^2x = 27

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