## Jadelynn 2 years ago Solve the exponential equation 9^2x = 27

1. Yahoo!

9 = 3^2 9^2x = 3^4x 27 = 3^3 Compare 4x = 3 x = 3/4

2. agent0smith

We have\[9^{2x}=27\] \[(3^{2})^{2x}=3^{3}\] \[3^{4x} = 3^{3}\] so 4x = 3

Can I get an explanation on how you did that?

9 is nothing but 3^2 and 27 is 3^3 so we need to make the base common to make it possible to solve for 'x'.... so............... 3^2(2x) = 3^3 therefore 3^4x = 3^3 since the base is the same, the exponents are equal;( since it is an equation and the left hand side is equal to the right hand side). so, 4x = 3 hence x = 3/4

did u understand my explanation @Jadelynn ? because if u didnt i can explain again

Yes I did. Thank you

7. agent0smith

thank you so much!!!

9. 66

how do you solve the equation 9^2x = 27

10. 66

using exponential and logarithmic form

11. agent0smith

@66 maybe post a new question... this one is four months old.

12. 66

13. agent0smith

14. 66

kk thx a lot

15. agent0smith

If you need to do it with logarithms, then take logarithms of both sides of 9^2x = 27

16. 66

how do you do that and its not solved above

17. 66

18. 66

??????????????????????????

19. 66

does anyone know how to solve for the equation 9^2x = 27