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rva.raghav

  • 2 years ago

The circuit parameters have the following values: VS=4.5V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V. Given that vIN=0.5V, what is the value of vOUT in Volts? unanswered Given that vIN=2V, what is the value of vOUT in Volts? unanswered What is the value of vIN in Volts when vOUT drops to VS2? unanswered Now you replace the ExpFET with a MOSFET with parameters K=1mAV2, and VT=1V. Assuming the MOSFET is operating in the saturation region, what is the value of vIN in volts when vOUT drops to VS2? (Recall that for a MOSFET in saturation: iD=K2(VGS−VT)2

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  1. rmpk
    • 2 years ago
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    You'll find the formulas here: http://openstudy.com/study#/updates/50d36174e4b0b19ec2190832

  2. rva.raghav
    • 2 years ago
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    i want answers

  3. rva.raghav
    • 2 years ago
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    please anyone

  4. rmpk
    • 2 years ago
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    Nobody is going to give you answers. If you can't even put values in a formula, then there's no point in passing this exam.

  5. rva.raghav
    • 2 years ago
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    just shetup and getlost

  6. rmpk
    • 2 years ago
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    Haha, lost your brain?

  7. rva.raghav
    • 2 years ago
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    the pronlem1 formula of q2 i cant understand

  8. rva.raghav
    • 2 years ago
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    sry rmpk

  9. bhu
    • 2 years ago
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    K,UTCFGRJYMB,Y

  10. Nurali
    • 2 years ago
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    @rva.raghav 1. 4.5 2. 2.7818 3. 2.1786 4. 3.1213 5. -2.7182 6. -1

  11. Nurali
    • 2 years ago
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    @rva.raghav if correct please click best response.

  12. rishikesh.147
    • one year ago
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    Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm b)iA =(-i2)*R/(2*R+rm) and V0=ia*rm c) part a) + part b) d)2R Q2 p1: Vs as vin<vt p2: v0 = vs-kr(e^((vin-vt)/vn)-1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: -kre^((vin-vt)/vn) p6: -kr(vin-vt) Q3 same as HP8p1 Q4 p1=V*R2/(R1+R2)*(1-e^(-(R1+R2)*t/(R1*R2*C))) p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(t-T)) p3=C*(V*R2/(R1+R2))*sin((t-T)*1/sqrt(L*C))/sqrt(L*C) Q5 E V B Y F Z

  13. rmpk
    • one year ago
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    @rishikesh.147 If you're so smart, give the formula for Q6. Wait, you can't, cause all you do is copy other's formulas, trying to get credit for them. Haha, you're so lame!

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