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anonymous
 3 years ago
The circuit parameters have the following values: VS=4.5V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V.
Given that vIN=0.5V, what is the value of vOUT in Volts?
unanswered
Given that vIN=2V, what is the value of vOUT in Volts?
unanswered
What is the value of vIN in Volts when vOUT drops to VS2?
unanswered
Now you replace the ExpFET with a MOSFET with parameters K=1mAV2, and VT=1V.
Assuming the MOSFET is operating in the saturation region, what is the value of vIN in volts when vOUT drops to VS2? (Recall that for a MOSFET in saturation: iD=K2(VGS−VT)2
anonymous
 3 years ago
The circuit parameters have the following values: VS=4.5V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V. Given that vIN=0.5V, what is the value of vOUT in Volts? unanswered Given that vIN=2V, what is the value of vOUT in Volts? unanswered What is the value of vIN in Volts when vOUT drops to VS2? unanswered Now you replace the ExpFET with a MOSFET with parameters K=1mAV2, and VT=1V. Assuming the MOSFET is operating in the saturation region, what is the value of vIN in volts when vOUT drops to VS2? (Recall that for a MOSFET in saturation: iD=K2(VGS−VT)2

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You'll find the formulas here: http://openstudy.com/study#/updates/50d36174e4b0b19ec2190832

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nobody is going to give you answers. If you can't even put values in a formula, then there's no point in passing this exam.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just shetup and getlost

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Haha, lost your brain?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the pronlem1 formula of q2 i cant understand

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@rva.raghav 1. 4.5 2. 2.7818 3. 2.1786 4. 3.1213 5. 2.7182 6. 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@rva.raghav if correct please click best response.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm b)iA =(i2)*R/(2*R+rm) and V0=ia*rm c) part a) + part b) d)2R Q2 p1: Vs as vin<vt p2: v0 = vskr(e^((vinvt)/vn)1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: kre^((vinvt)/vn) p6: kr(vinvt) Q3 same as HP8p1 Q4 p1=V*R2/(R1+R2)*(1e^((R1+R2)*t/(R1*R2*C))) p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(tT)) p3=C*(V*R2/(R1+R2))*sin((tT)*1/sqrt(L*C))/sqrt(L*C) Q5 E V B Y F Z

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@rishikesh.147 If you're so smart, give the formula for Q6. Wait, you can't, cause all you do is copy other's formulas, trying to get credit for them. Haha, you're so lame!
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