Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
rva.raghav
Group Title
The circuit parameters have the following values: VS=4.5V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V.
Given that vIN=0.5V, what is the value of vOUT in Volts?
unanswered
Given that vIN=2V, what is the value of vOUT in Volts?
unanswered
What is the value of vIN in Volts when vOUT drops to VS2?
unanswered
Now you replace the ExpFET with a MOSFET with parameters K=1mAV2, and VT=1V.
Assuming the MOSFET is operating in the saturation region, what is the value of vIN in volts when vOUT drops to VS2? (Recall that for a MOSFET in saturation: iD=K2(VGS−VT)2
 one year ago
 one year ago
rva.raghav Group Title
The circuit parameters have the following values: VS=4.5V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V. Given that vIN=0.5V, what is the value of vOUT in Volts? unanswered Given that vIN=2V, what is the value of vOUT in Volts? unanswered What is the value of vIN in Volts when vOUT drops to VS2? unanswered Now you replace the ExpFET with a MOSFET with parameters K=1mAV2, and VT=1V. Assuming the MOSFET is operating in the saturation region, what is the value of vIN in volts when vOUT drops to VS2? (Recall that for a MOSFET in saturation: iD=K2(VGS−VT)2
 one year ago
 one year ago

This Question is Closed

rmpk Group TitleBest ResponseYou've already chosen the best response.0
You'll find the formulas here: http://openstudy.com/study#/updates/50d36174e4b0b19ec2190832
 one year ago

rva.raghav Group TitleBest ResponseYou've already chosen the best response.0
i want answers
 one year ago

rva.raghav Group TitleBest ResponseYou've already chosen the best response.0
please anyone
 one year ago

rmpk Group TitleBest ResponseYou've already chosen the best response.0
Nobody is going to give you answers. If you can't even put values in a formula, then there's no point in passing this exam.
 one year ago

rva.raghav Group TitleBest ResponseYou've already chosen the best response.0
just shetup and getlost
 one year ago

rmpk Group TitleBest ResponseYou've already chosen the best response.0
Haha, lost your brain?
 one year ago

rva.raghav Group TitleBest ResponseYou've already chosen the best response.0
the pronlem1 formula of q2 i cant understand
 one year ago

rva.raghav Group TitleBest ResponseYou've already chosen the best response.0
sry rmpk
 one year ago

bhu Group TitleBest ResponseYou've already chosen the best response.0
K,UTCFGRJYMB,Y
 one year ago

Nurali Group TitleBest ResponseYou've already chosen the best response.5
@rva.raghav 1. 4.5 2. 2.7818 3. 2.1786 4. 3.1213 5. 2.7182 6. 1
 one year ago

Nurali Group TitleBest ResponseYou've already chosen the best response.5
@rva.raghav if correct please click best response.
 one year ago

rishikesh.147 Group TitleBest ResponseYou've already chosen the best response.0
Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm b)iA =(i2)*R/(2*R+rm) and V0=ia*rm c) part a) + part b) d)2R Q2 p1: Vs as vin<vt p2: v0 = vskr(e^((vinvt)/vn)1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: kre^((vinvt)/vn) p6: kr(vinvt) Q3 same as HP8p1 Q4 p1=V*R2/(R1+R2)*(1e^((R1+R2)*t/(R1*R2*C))) p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(tT)) p3=C*(V*R2/(R1+R2))*sin((tT)*1/sqrt(L*C))/sqrt(L*C) Q5 E V B Y F Z
 one year ago

rmpk Group TitleBest ResponseYou've already chosen the best response.0
@rishikesh.147 If you're so smart, give the formula for Q6. Wait, you can't, cause all you do is copy other's formulas, trying to get credit for them. Haha, you're so lame!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.