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mathnoob1

  • 3 years ago

anyone can explain how this? ( (1/(1-2sin²θ)))-1 / ((2sinθ)/(1-2sinθ)) <-----?? = sinθ become this? ((1-1+2sin²θ)/(2sinθ))=sinθ

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  1. ZeHanz
    • 3 years ago
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    Is this the expression you've got:\[\frac{ 1 }{ 1-2\sin^2 \theta }-\frac{ 1 }{ \frac{ 2\sin \theta }{ 1-2\sin \theta } }=\frac{ 1 }{ 1-2\sin^2 \theta }-\frac{ 1-2\sin \theta }{ 2\sin \theta }\]

  2. jishan
    • 3 years ago
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    |dw:1356196967021:dw|

  3. jishan
    • 3 years ago
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    |dw:1356197132808:dw|

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