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If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and third equations, then the second and third equations.
x – y + 2z = –2
2x + 2y + z = 7
3x + 3y – z = 3
 one year ago
 one year ago
If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and third equations, then the second and third equations. x – y + 2z = –2 2x + 2y + z = 7 3x + 3y – z = 3
 one year ago
 one year ago

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hartnnBest ResponseYou've already chosen the best response.1
add 2nd and 3rd equation, what u get ?
 one year ago

kelliegirl33Best ResponseYou've already chosen the best response.1
x  y + 2z =  2 2x + 2y + z = 7 3x + 3y  z = 3  Step 1: add 1st and 3rd equation multiplying if necessary to eliminate z x  y + 2z = 2 3x + 3y z = 3 >(2)3x + 3y  z = 3  x  y + 2z = 2 6x + 6y  2z = 6 (result of multiplying 2nd equation by 2)  7x + 5y = 4 ====> new equation resulting from 1st and 3rd equation Now for the 2nd and 3rd equation..... 2x + 2y + z = 7 3x + 3y  z = 3 no multiplying is needed because the z's cancel out 5x + 5y = 10 ===> new equation resulting from 2nd and 3rd equation easy enough :)
 one year ago

SkysthelimitBest ResponseYou've already chosen the best response.0
thanks That helped a lot.
 one year ago

kelliegirl33Best ResponseYou've already chosen the best response.1
no problem...anytime :)
 one year ago
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