If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and third equations, then the second and third equations. x – y + 2z = –2 2x + 2y + z = 7 3x + 3y – z = 3
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
add 2nd and 3rd equation, what u get ?
x - y + 2z = - 2 2x + 2y + z = 7 3x + 3y - z = 3 -------------- Step 1: add 1st and 3rd equation multiplying if necessary to eliminate z x - y + 2z = -2 3x + 3y -z = 3 --->(2)3x + 3y - z = 3 --------------- x - y + 2z = -2 6x + 6y - 2z = 6 (result of multiplying 2nd equation by 2) -------------- 7x + 5y = 4 ====> new equation resulting from 1st and 3rd equation Now for the 2nd and 3rd equation..... 2x + 2y + z = 7 3x + 3y - z = 3 -------------no multiplying is needed because the z's cancel out 5x + 5y = 10 ===> new equation resulting from 2nd and 3rd equation easy enough :)