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iheartfood

  • 2 years ago

Write the equation for an ellipse with co-vertices (0,-3) and (0,3), major axis of length 10.

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  1. iheartfood
    • 2 years ago
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    @jim_thompson5910 :)

  2. jim_thompson5910
    • 2 years ago
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    where is the center?

  3. iheartfood
    • 2 years ago
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    idk.. it doesn't say... it just says what i typed in :/

  4. jim_thompson5910
    • 2 years ago
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    i know, you have to find it

  5. jim_thompson5910
    • 2 years ago
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    the co-vertices lie along the minor axis

  6. iheartfood
    • 2 years ago
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    ok, how do we do that?

  7. jim_thompson5910
    • 2 years ago
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    the midpoint of this minor axis is where the center is

  8. iheartfood
    • 2 years ago
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    minor is vertical or horizontal?

  9. jim_thompson5910
    • 2 years ago
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    (0,-3) and (0,3) lie on what line?

  10. iheartfood
    • 2 years ago
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    so would the center be (0,0) ??

  11. jim_thompson5910
    • 2 years ago
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    yep

  12. iheartfood
    • 2 years ago
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    the x-axis?

  13. jim_thompson5910
    • 2 years ago
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    no, you have it flipped

  14. iheartfood
    • 2 years ago
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    okay so how do i write this equation?? oh the y axis?

  15. jim_thompson5910
    • 2 years ago
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    so the minor axis is vertical

  16. jim_thompson5910
    • 2 years ago
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    the major must be horizontal

  17. iheartfood
    • 2 years ago
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    ohh okay :) so its on the major axis?

  18. jim_thompson5910
    • 2 years ago
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    what is

  19. iheartfood
    • 2 years ago
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    (0,-3) and (0,3) ?

  20. jim_thompson5910
    • 2 years ago
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    no they are on the minor axis because they are co-vertices

  21. jim_thompson5910
    • 2 years ago
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    not vertices

  22. iheartfood
    • 2 years ago
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    ohh okay i see... what do we do now??

  23. jim_thompson5910
    • 2 years ago
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    how long is the minor axis?

  24. iheartfood
    • 2 years ago
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    idk :/ how do i find that?? i just know the major axis is 10...

  25. jim_thompson5910
    • 2 years ago
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    what's the distance between the co-vertices?

  26. iheartfood
    • 2 years ago
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    6? so is 6 the length of the minor axis?

  27. jim_thompson5910
    • 2 years ago
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    yes good

  28. jim_thompson5910
    • 2 years ago
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    cut that in half to get 3 that's the length of the semi-minor axis

  29. jim_thompson5910
    • 2 years ago
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    since the minor axis is vertical, this value of 3 corresponds to the value of b (which is paired with the y term below) (x-h)^2/(a^2) + (y-k)^2/(b^2) = 1

  30. jim_thompson5910
    • 2 years ago
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    so b = 3

  31. jim_thompson5910
    • 2 years ago
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    you know the center is (0,0) because you just found this, so (h,k) = (0,0)

  32. iheartfood
    • 2 years ago
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    okay :) so far we have this? (x-0)^2/(a^2) + (y-0)^2/(3^2)=1 ??

  33. jim_thompson5910
    • 2 years ago
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    good, the only thing you need is 'a'

  34. iheartfood
    • 2 years ago
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    how do we find that? do we square root 10? if so, can i just write sq.rt.10?

  35. jim_thompson5910
    • 2 years ago
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    no, the length of the major axis is 10 the length of the semi-major axis is ____

  36. iheartfood
    • 2 years ago
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    5?

  37. jim_thompson5910
    • 2 years ago
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    so a = 5

  38. iheartfood
    • 2 years ago
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    okay so is this my final equation??|dw:1356131103670:dw| is that it?? or do i need to simplify it more?

  39. jim_thompson5910
    • 2 years ago
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    you can simplify it more if you want

  40. jim_thompson5910
    • 2 years ago
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    |dw:1356131176856:dw|

  41. iheartfood
    • 2 years ago
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    but when it says write the equation, what format do they want it in?

  42. jim_thompson5910
    • 2 years ago
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    there are many formats, but that's probably the best one

  43. jim_thompson5910
    • 2 years ago
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    because you can tell it's an ellipse and you can use it to read off the center, major axis, minor axis lengths, etc etc

  44. iheartfood
    • 2 years ago
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    the simplified version?

  45. jim_thompson5910
    • 2 years ago
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    yeah

  46. iheartfood
    • 2 years ago
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    kk so we are done now?? htats it?

  47. jim_thompson5910
    • 2 years ago
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    yes

  48. iheartfood
    • 2 years ago
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    kk thank youu :)

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