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nope, it's correct.....

Tk have you come to save me? :P

Determinant? It's an inverse.

I thought taking the inverse is the same as taking the determinant?

I guess I konfused myself again :p.

1/ad-bc [d -b -c a]?

:P

ic, so what happens since there is none?

I got 0 so that makes sense.

3x1 +9x2= y

-2x1 - 6x2

I'm soo konfused.......

yeah I figured that out 2/7-3*t is x1 and x2 is t.

part b we already solved the normal eq, now I'm working on the error part 3...

are you taking the error to be \[\|Ax-b\|\]

first it shows the error vector, then shows that.

is that asking for the norm?

then just compute it...you have all the pieces
yes

does that error play into it, or what exactly am I computing the norm with?

error vector*

you are computing \(\|Ax-b\|\)
where for any vector \(v=\)
\[\|v\|=\sqrt{a^2+b^2+c^2}\]

SO I guess we do use that error vector then lol.

(1/7)*sqrt(42)

0.9258

seems fine

Thanks for the help :).