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yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0oh, maximum positive argument of z satisfying z4=re(z)? i am sorry. messed up a little

nitz
 one year ago
Best ResponseYou've already chosen the best response.0mod((x+iy)4)=x mod((x4)+iy))=x sqrt((x4)^2+y^2)=x

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0i get 168x+y^2.. how do i proceed?

nitz
 one year ago
Best ResponseYou've already chosen the best response.0sorry that i was thinking could be a way to solve problem but i was wrong....................now i have found a way to solve it .................but dont know how to draw figure here??????????

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0you can draw it by clicking draw.. right below the box yu type in..

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0@nitz can you help me please?

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0options are 30 60,45,90..

experimentX
 one year ago
Best ResponseYou've already chosen the best response.3dw:1356176367696:dw

stgreen
 one year ago
Best ResponseYou've already chosen the best response.2think again z4=(x4)+iy not x+i(y+4)

experimentX
 one year ago
Best ResponseYou've already chosen the best response.3woops!! sorry .. may fault!! (x4)^2 + y^2 = x^2 use this relation to maximize this function Arg(z) = arctan(y/x)

experimentX
 one year ago
Best ResponseYou've already chosen the best response.3http://www.wolframalpha.com/input/?i=maximize+arctan%28y%2Fx%29%2C+8x%2B16+%2B+y^2+%3D+0

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0@experimentX how did the site maximise it.. i mean maximing wrt a function. how to do that?
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