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yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0oh, maximum positive argument of z satisfying z4=re(z)? i am sorry. messed up a little

nitz
 2 years ago
Best ResponseYou've already chosen the best response.0mod((x+iy)4)=x mod((x4)+iy))=x sqrt((x4)^2+y^2)=x

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0i get 168x+y^2.. how do i proceed?

nitz
 2 years ago
Best ResponseYou've already chosen the best response.0sorry that i was thinking could be a way to solve problem but i was wrong....................now i have found a way to solve it .................but dont know how to draw figure here??????????

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0you can draw it by clicking draw.. right below the box yu type in..

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0@nitz can you help me please?

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0options are 30 60,45,90..

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.3dw:1356176367696:dw

stgreen
 2 years ago
Best ResponseYou've already chosen the best response.2think again z4=(x4)+iy not x+i(y+4)

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.3woops!! sorry .. may fault!! (x4)^2 + y^2 = x^2 use this relation to maximize this function Arg(z) = arctan(y/x)

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.3http://www.wolframalpha.com/input/?i=maximize+arctan%28y%2Fx%29%2C+8x%2B16+%2B+y^2+%3D+0

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.0@experimentX how did the site maximise it.. i mean maximing wrt a function. how to do that?
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