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yrelhan4

  • 3 years ago

|z-4|=re(z) maximim +arg of complex satisfying this??

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  1. yrelhan4
    • 3 years ago
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    oh, maximum positive argument of z satisfying |z-4|=re(z)? i am sorry. messed up a little

  2. nitz
    • 3 years ago
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    mod((x+iy)-4)=x mod((x-4)+iy))=x sqrt((x-4)^2+y^2)=x

  3. yrelhan4
    • 3 years ago
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    i get 16-8x+y^2.. how do i proceed?

  4. yrelhan4
    • 3 years ago
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    =0 *

  5. yrelhan4
    • 3 years ago
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    @nitz ??

  6. nitz
    • 3 years ago
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    sorry that i was thinking could be a way to solve problem but i was wrong....................now i have found a way to solve it .................but dont know how to draw figure here??????????

  7. yrelhan4
    • 3 years ago
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    you can draw it by clicking draw.. right below the box yu type in..

  8. yrelhan4
    • 3 years ago
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    @nitz can you help me please?

  9. yrelhan4
    • 3 years ago
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    options are 30 60,45,90..

  10. experimentX
    • 3 years ago
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    |dw:1356176367696:dw|

  11. stgreen
    • 3 years ago
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    think again z-4=(x-4)+iy not x+i(y+4)

  12. experimentX
    • 3 years ago
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    woops!! sorry .. may fault!! (x-4)^2 + y^2 = x^2 use this relation to maximize this function Arg(z) = arctan(y/x)

  13. experimentX
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=maximize+arctan%28y%2Fx%29%2C+-8x%2B16+%2B+y^2+%3D+0

  14. yrelhan4
    • 3 years ago
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    @experimentX how did the site maximise it.. i mean maximing wrt a function. how to do that?

  15. yrelhan4
    • 3 years ago
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    got it!!

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