anonymous
  • anonymous
Help in Question 2:
MIT 6.002 Circuits and Electronics, Spring 2007
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
he circuit parameters have the following values: VS=4V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V.
anonymous
  • anonymous
Given that vIN=0.5V, what is the value of vOUT in Volts? Given that vIN=2V, what is the value of vOUT in Volts? What is the value of vIN in Volts when vOUT drops to VS/2? Now you replace the ExpFET with a MOSFET with parameters K=1mA, Vt = 1v: Again, the circuit parameters are: VS=4V and R=1kΩ, and the ExpFET parameters are K=1mA, VT=1V and VN=1V. Given that VIN=2V, what is the small-signal gain (vout/vin) of this circuit? Given that VIN=2V and assuming that the MOSFET is operating in saturation, what is the small-signal gain (vout/vin) of this circuit?
anonymous
  • anonymous
p1: Vs p2: v0 = vs-kr(e^((vin-vt)/vn)-1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: -kre^((vin-vt)/vn) p6: -kr(vin-vt) put your values in it

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Thank you!!!
anonymous
  • anonymous
Hey, you, I finished my exam and I got a 60%, but I have a question, wich were the correct answer to problem Q2( b) The circuit parameters have the following values: VS=4V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V. and VIN =2V My answer was 4.39 and was wrong For b) I used v0 = vs-kr(e^((vin-vt)/vn)-1) and I got the wron answer three times, 4.39, The another a,c,d,e were corret using the above formulas except b).

Looking for something else?

Not the answer you are looking for? Search for more explanations.