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JoãoVitorMC Group TitleBest ResponseYou've already chosen the best response.0
he circuit parameters have the following values: VS=4V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V.
 one year ago

JoãoVitorMC Group TitleBest ResponseYou've already chosen the best response.0
Given that vIN=0.5V, what is the value of vOUT in Volts? Given that vIN=2V, what is the value of vOUT in Volts? What is the value of vIN in Volts when vOUT drops to VS/2? Now you replace the ExpFET with a MOSFET with parameters K=1mA, Vt = 1v: Again, the circuit parameters are: VS=4V and R=1kΩ, and the ExpFET parameters are K=1mA, VT=1V and VN=1V. Given that VIN=2V, what is the smallsignal gain (vout/vin) of this circuit? Given that VIN=2V and assuming that the MOSFET is operating in saturation, what is the smallsignal gain (vout/vin) of this circuit?
 one year ago

kpkishanpandya5 Group TitleBest ResponseYou've already chosen the best response.2
p1: Vs p2: v0 = vskr(e^((vinvt)/vn)1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: kre^((vinvt)/vn) p6: kr(vinvt) put your values in it
 one year ago

JoãoVitorMC Group TitleBest ResponseYou've already chosen the best response.0
Thank you!!!
 one year ago

peruana Group TitleBest ResponseYou've already chosen the best response.0
Hey, you, I finished my exam and I got a 60%, but I have a question, wich were the correct answer to problem Q2( b) The circuit parameters have the following values: VS=4V and R=1kΩ, and the ExpFET parameters are: K=1mA, VT=1V and VN=1V. and VIN =2V My answer was 4.39 and was wrong For b) I used v0 = vskr(e^((vinvt)/vn)1) and I got the wron answer three times, 4.39, The another a,c,d,e were corret using the above formulas except b).
 one year ago
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