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anonymous
 3 years ago
Assume that in the circuit above, V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω
anonymous
 3 years ago
Assume that in the circuit above, V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@salman.abid12 , just a sec, I'll calculate for you

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@salman.abid12 C  7.94645719261

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@salman.abid12 D  0.05354280739

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Dude, I'm working on this in the airport :)) I'm the guy that posted the formulas here (but they were deleted), so the formulas are correct. Hope my calculations are correct too, but I don't have a calculator.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0V0=5V, T=0.5ms, Rw=1Ω, Lw=1mH and RL=1Ω. ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@rmpk means there is some risk... ok let me chek it..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yupeeeeee! thanks a lot dude @rmpk..... that were correct.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No problem, glad it was fine.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm b)iA =(i2)*R/(2*R+rm) and V0=ia*rm c) part a) + part b) d)2R Q2 p1: Vs as vin<vt p2: v0 = vskr(e^((vinvt)/vn)1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: kre^((vinvt)/vn) p6: kr(vinvt) Q3 same as HP8p1 Q4 p1=V*R2/(R1+R2)*(1e^((R1+R2)*t/(R1*R2*C))) p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(tT)) p3=C*(V*R2/(R1+R2))*sin((tT)*1/sqrt(L*C))/sqrt(L*C) Q5 E V B Y F Z Q6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What about Q6 A and B?
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