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Assume that in the circuit above, V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω
 one year ago
 one year ago
Assume that in the circuit above, V0=10V, T=0.5ms, Rw=1Ω, Lw=0.5mH and RL=4Ω
 one year ago
 one year ago

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rmpkBest ResponseYou've already chosen the best response.1
@salman.abid12 , just a sec, I'll calculate for you
 one year ago

rmpkBest ResponseYou've already chosen the best response.1
@salman.abid12 C  7.94645719261
 one year ago

rmpkBest ResponseYou've already chosen the best response.1
@salman.abid12 D  0.05354280739
 one year ago

rmpkBest ResponseYou've already chosen the best response.1
Dude, I'm working on this in the airport :)) I'm the guy that posted the formulas here (but they were deleted), so the formulas are correct. Hope my calculations are correct too, but I don't have a calculator.
 one year ago

jayapavanBest ResponseYou've already chosen the best response.0
V0=5V, T=0.5ms, Rw=1Ω, Lw=1mH and RL=1Ω. ???
 one year ago

salman.abid12Best ResponseYou've already chosen the best response.0
@rmpk means there is some risk... ok let me chek it..
 one year ago

salman.abid12Best ResponseYou've already chosen the best response.0
yupeeeeee! thanks a lot dude @rmpk..... that were correct.
 one year ago

rmpkBest ResponseYou've already chosen the best response.1
No problem, glad it was fine.
 one year ago

rishikesh.147Best ResponseYou've already chosen the best response.2
Q1 a)ia=2*i1*R/(2*R+rm) and vo=ia*rm b)iA =(i2)*R/(2*R+rm) and V0=ia*rm c) part a) + part b) d)2R Q2 p1: Vs as vin<vt p2: v0 = vskr(e^((vinvt)/vn)1) p3: vin = ln(vs/2kr +1)vn+vt p4: vin=sqrt(vs/kr)+vt p5: kre^((vinvt)/vn) p6: kr(vinvt) Q3 same as HP8p1 Q4 p1=V*R2/(R1+R2)*(1e^((R1+R2)*t/(R1*R2*C))) p2=(V*R2/(R1+R2))*cos(1/sqrt(L*C)*(tT)) p3=C*(V*R2/(R1+R2))*sin((tT)*1/sqrt(L*C))/sqrt(L*C) Q5 E V B Y F Z Q6
 one year ago

jordankaushikBest ResponseYou've already chosen the best response.0
What about Q6 A and B?
 one year ago
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