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julliemyers

  • 2 years ago

This may seem stupid but can anyone help?? I have to divide 10 by 5 minutes and 54 seconds????

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  1. julliemyers
    • 2 years ago
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    @nubeer

  2. ParthKohli
    • 2 years ago
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    Heh, I get it.

  3. ParthKohli
    • 2 years ago
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    \(5 \min 54 \sec = 5 \dfrac{54}{60} = 5.9\)

  4. ParthKohli
    • 2 years ago
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    Is it this?

  5. hba
    • 2 years ago
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    @ParthKohli Yeah right.

  6. julliemyers
    • 2 years ago
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    Im doing a Algebra2 experiment and i have to divide my average time by 10 Here are my times 5 min 54 sec 4min 55sec 3min 30sec so when i divide these all by 10 do i put the time in decimal form? Like 5min 54 sec= 5.54??

  7. ParthKohli
    • 2 years ago
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    Essentially, \(5 \min 54 \sec = {5 } + \dfrac{54}{60}\) as we're expressing the seconds as a fraction.

  8. ParthKohli
    • 2 years ago
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    Now, you can simplify \(\dfrac{54}{60}\).

  9. julliemyers
    • 2 years ago
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    so, 5.9 divide by 10? and i get .59? and that would be my awsner for that one

  10. ParthKohli
    • 2 years ago
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    BTW, it'd be dividing 5 min 54 sec by 10, not the vice-versa.

  11. ParthKohli
    • 2 years ago
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    Yes, that'd be your answer :) @julliemyers

  12. julliemyers
    • 2 years ago
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    oh ok then so just to make sure i get the rest correct let me do them and will u check them?

  13. nubeer
    • 2 years ago
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    hmm it says to divide the average time by 10.. so that might not be the answer.. first you have to convert all your times into decimal

  14. ParthKohli
    • 2 years ago
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    Sure! =)

  15. nagdy1
    • 2 years ago
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    ((10/5) minute) + (54 seconds) = 2.9 minutes

  16. ParthKohli
    • 2 years ago
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    Oh, yes.

  17. ParthKohli
    • 2 years ago
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    Didn't see that question below.

  18. julliemyers
    • 2 years ago
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    no i had 3 trials and i have to divide 10 by indivaual times

  19. nagdy1
    • 2 years ago
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    serach on google divide 10 by 5 minutes and 54 seconds

  20. ParthKohli
    • 2 years ago
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    Okay... so can you divide the other times by 10 after converting them and take the average of all figures you get?

  21. julliemyers
    • 2 years ago
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    hang on ill show u my table

  22. julliemyers
    • 2 years ago
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  23. nagdy1
    • 2 years ago
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    5 minutes 10 seconds divide it by 5 = 1 minute 2 seconds.

  24. ParthKohli
    • 2 years ago
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    Oh, so that is the question.

  25. julliemyers
    • 2 years ago
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    this is the directions . For each trial, use a stopwatch to record the number of seconds it takes for the pendulum to complete 10 full swings. Record each time in the i rst column of the table provided on the next page. Next, i nd and record the average of the three times you listed. Finally, divide the average time by 10 to determine the period of the pendulum. Repeat the procedure using two coins, then using three coins, recording the data in the second and third columns, respectively. Does it appear that the weight of the bob af ected the period of the pendulum? What factors other than the weight might af ect the period of the pendulum?

  26. ParthKohli
    • 2 years ago
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    So you have to find the average period. It'd be 5 min 54 sec by 10.

  27. julliemyers
    • 2 years ago
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    yes each collum had their own average time

  28. ParthKohli
    • 2 years ago
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    Then I'm afraid you'd have to complete this experiment by yourself.

  29. ParthKohli
    • 2 years ago
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    Did you do this experiment?

  30. nubeer
    • 2 years ago
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    hmm ok i have a question.. something don't seem right. in the trial 1 with 1 coin the time u have wrote is for 10 swings?

  31. julliemyers
    • 2 years ago
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    yes it was in the file i attatched i just needed help on how i would divide time by 10

  32. ParthKohli
    • 2 years ago
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    But that wouldn't be the time for 10 swings. Though there's a cheat: You can divide it by 3. ;)

  33. dewron
    • 2 years ago
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    add all noted times with seconds as fraction and then divide by 10. here is your answer :)

  34. nubeer
    • 2 years ago
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    @julliemyers wel i think the average time u have found for 10 swings in that file is wrong.. u need to check that again.

  35. ParthKohli
    • 2 years ago
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    You can add 3 noted times and divide by 3 -- no one would realize :D

  36. ParthKohli
    • 2 years ago
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    @nubeer: Seems like julliemyers has summed up the three noted times in the above rows.

  37. nubeer
    • 2 years ago
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    yup she did that.. she just forgot to divide by 3

  38. ParthKohli
    • 2 years ago
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    Mhm

  39. julliemyers
    • 2 years ago
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    @nubeer it doesnt say i need to divide by 3 tho?

  40. nubeer
    • 2 years ago
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    i know it don't say and it will never say.. the Word Average itself says it.. Average = Total time/ no. of times experiment performed.. means you would add up the time of all the 3 trials and then divide it by 3.. IF INCASE.. there was a 4th trial then you would add all the 4 times and divide by 4... you have to do this where ever the average word comes up

  41. julliemyers
    • 2 years ago
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    ohh Yea i remeber that. So for ex 5 min 54sec would be 5.54/3 =1.846 then i devide that by 10?? =0.1846????

  42. nubeer
    • 2 years ago
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    yes..

  43. julliemyers
    • 2 years ago
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    ok i think i have got it lol -.-

  44. nubeer
    • 2 years ago
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    lol good :)

  45. ParthKohli
    • 2 years ago
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    @julliemyers No

  46. julliemyers
    • 2 years ago
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    @ParthKohli No to what? Im wrong?????

  47. nubeer
    • 2 years ago
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    lol that was 5.9 .. the total time.

  48. ParthKohli
    • 2 years ago
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    It's not \(5.54\); it's \(5.9\)

  49. ParthKohli
    • 2 years ago
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    And you don't have to further divide by 10.

  50. ParthKohli
    • 2 years ago
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    Got it? :D

  51. nubeer
    • 2 years ago
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    lol she have to divide by 10 to find the time period.. @ParthKohli

  52. julliemyers
    • 2 years ago
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    Im so confused (-.-)

  53. nubeer
    • 2 years ago
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    First add all the time , trial 1,2,3 that would be 5.9 and divide it by 3.. the value you will get you will put that against this row "Average time complete 10 full swings"

  54. ParthKohli
    • 2 years ago
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    Oh yes

  55. nubeer
    • 2 years ago
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    Now.. the value in this row "Average time complete 10 full swings" you would divide it by 10 and put them in this row "Period of pendulum "

  56. ParthKohli
    • 2 years ago
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    @nubeer: My medal increased your SS :P

  57. nubeer
    • 2 years ago
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    lol does it ? really? hahah i dont think so.. lol i never work on medals but still thank you...

  58. julliemyers
    • 2 years ago
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    Im spose to have 3 periods of pendulum times, I dont think i add up all my averages. i think im spose to have 3

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  59. nubeer
    • 2 years ago
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    hmmm .. :( not getting you.. ok look the file you have posted and see the row average time for 10 swings what value u have in there?

  60. julliemyers
    • 2 years ago
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    yes those r the values added of the coin 1 coin 2 and coin 3

  61. nubeer
    • 2 years ago
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    ok.. now 5 min 54 secs convert in decimal you will get 5.9 right? you did that before now divide 5.9 by 3... becasue that total time is for 3 trials.. getting it?

  62. julliemyers
    • 2 years ago
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    i get 1.966666666 = 1.97

  63. julliemyers
    • 2 years ago
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    so 1.97 would go in the period of pendulum collum???

  64. nubeer
    • 2 years ago
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    ok.. good.. now this is average time for 10 swings.. ok? now for the time period of pendulum.. this means the time period for just 1 swing so u divide 1.97 by 10

  65. julliemyers
    • 2 years ago
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    .197

  66. nubeer
    • 2 years ago
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    yes

  67. julliemyers
    • 2 years ago
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    Should i have 5.9, 4.9, 3.5In the average collum? Instead of the minutes and seconds or should i leave it how it is

  68. nubeer
    • 2 years ago
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    hmm i told u these are not average.. 5.9/3 would be the aveage so 1.97 mins is the average of 10 swings.

  69. julliemyers
    • 2 years ago
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    ok thats what i was wondering lol i feel stupid but i understand it now lol

  70. nubeer
    • 2 years ago
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    lol no worries..

  71. julliemyers
    • 2 years ago
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    ok so i fixed it take a look

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  72. nubeer
    • 2 years ago
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    yup looks ok now.. this all are in mins. :)

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