anonymous
  • anonymous
This may seem stupid but can anyone help?? I have to divide 10 by 5 minutes and 54 seconds????
Mathematics
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anonymous
  • anonymous
This may seem stupid but can anyone help?? I have to divide 10 by 5 minutes and 54 seconds????
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
ParthKohli
  • ParthKohli
Heh, I get it.
ParthKohli
  • ParthKohli
\(5 \min 54 \sec = 5 \dfrac{54}{60} = 5.9\)

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ParthKohli
  • ParthKohli
Is it this?
hba
  • hba
@ParthKohli Yeah right.
anonymous
  • anonymous
Im doing a Algebra2 experiment and i have to divide my average time by 10 Here are my times 5 min 54 sec 4min 55sec 3min 30sec so when i divide these all by 10 do i put the time in decimal form? Like 5min 54 sec= 5.54??
ParthKohli
  • ParthKohli
Essentially, \(5 \min 54 \sec = {5 } + \dfrac{54}{60}\) as we're expressing the seconds as a fraction.
ParthKohli
  • ParthKohli
Now, you can simplify \(\dfrac{54}{60}\).
anonymous
  • anonymous
so, 5.9 divide by 10? and i get .59? and that would be my awsner for that one
ParthKohli
  • ParthKohli
BTW, it'd be dividing 5 min 54 sec by 10, not the vice-versa.
ParthKohli
  • ParthKohli
Yes, that'd be your answer :) @julliemyers
anonymous
  • anonymous
oh ok then so just to make sure i get the rest correct let me do them and will u check them?
nubeer
  • nubeer
hmm it says to divide the average time by 10.. so that might not be the answer.. first you have to convert all your times into decimal
ParthKohli
  • ParthKohli
Sure! =)
anonymous
  • anonymous
((10/5) minute) + (54 seconds) = 2.9 minutes
ParthKohli
  • ParthKohli
Oh, yes.
ParthKohli
  • ParthKohli
Didn't see that question below.
anonymous
  • anonymous
no i had 3 trials and i have to divide 10 by indivaual times
anonymous
  • anonymous
serach on google divide 10 by 5 minutes and 54 seconds
ParthKohli
  • ParthKohli
Okay... so can you divide the other times by 10 after converting them and take the average of all figures you get?
anonymous
  • anonymous
hang on ill show u my table
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
5 minutes 10 seconds divide it by 5 = 1 minute 2 seconds.
ParthKohli
  • ParthKohli
Oh, so that is the question.
anonymous
  • anonymous
this is the directions . For each trial, use a stopwatch to record the number of seconds it takes for the pendulum to complete 10 full swings. Record each time in the i rst column of the table provided on the next page. Next, i nd and record the average of the three times you listed. Finally, divide the average time by 10 to determine the period of the pendulum. Repeat the procedure using two coins, then using three coins, recording the data in the second and third columns, respectively. Does it appear that the weight of the bob af ected the period of the pendulum? What factors other than the weight might af ect the period of the pendulum?
ParthKohli
  • ParthKohli
So you have to find the average period. It'd be 5 min 54 sec by 10.
anonymous
  • anonymous
yes each collum had their own average time
ParthKohli
  • ParthKohli
Then I'm afraid you'd have to complete this experiment by yourself.
ParthKohli
  • ParthKohli
Did you do this experiment?
nubeer
  • nubeer
hmm ok i have a question.. something don't seem right. in the trial 1 with 1 coin the time u have wrote is for 10 swings?
anonymous
  • anonymous
yes it was in the file i attatched i just needed help on how i would divide time by 10
ParthKohli
  • ParthKohli
But that wouldn't be the time for 10 swings. Though there's a cheat: You can divide it by 3. ;)
anonymous
  • anonymous
add all noted times with seconds as fraction and then divide by 10. here is your answer :)
nubeer
  • nubeer
@julliemyers wel i think the average time u have found for 10 swings in that file is wrong.. u need to check that again.
ParthKohli
  • ParthKohli
You can add 3 noted times and divide by 3 -- no one would realize :D
ParthKohli
  • ParthKohli
@nubeer: Seems like julliemyers has summed up the three noted times in the above rows.
nubeer
  • nubeer
yup she did that.. she just forgot to divide by 3
ParthKohli
  • ParthKohli
Mhm
anonymous
  • anonymous
@nubeer it doesnt say i need to divide by 3 tho?
nubeer
  • nubeer
i know it don't say and it will never say.. the Word Average itself says it.. Average = Total time/ no. of times experiment performed.. means you would add up the time of all the 3 trials and then divide it by 3.. IF INCASE.. there was a 4th trial then you would add all the 4 times and divide by 4... you have to do this where ever the average word comes up
anonymous
  • anonymous
ohh Yea i remeber that. So for ex 5 min 54sec would be 5.54/3 =1.846 then i devide that by 10?? =0.1846????
nubeer
  • nubeer
yes..
anonymous
  • anonymous
ok i think i have got it lol -.-
nubeer
  • nubeer
lol good :)
ParthKohli
  • ParthKohli
anonymous
  • anonymous
@ParthKohli No to what? Im wrong?????
nubeer
  • nubeer
lol that was 5.9 .. the total time.
ParthKohli
  • ParthKohli
It's not \(5.54\); it's \(5.9\)
ParthKohli
  • ParthKohli
And you don't have to further divide by 10.
ParthKohli
  • ParthKohli
Got it? :D
nubeer
  • nubeer
lol she have to divide by 10 to find the time period.. @ParthKohli
anonymous
  • anonymous
Im so confused (-.-)
nubeer
  • nubeer
First add all the time , trial 1,2,3 that would be 5.9 and divide it by 3.. the value you will get you will put that against this row "Average time complete 10 full swings"
ParthKohli
  • ParthKohli
Oh yes
nubeer
  • nubeer
Now.. the value in this row "Average time complete 10 full swings" you would divide it by 10 and put them in this row "Period of pendulum "
ParthKohli
  • ParthKohli
@nubeer: My medal increased your SS :P
nubeer
  • nubeer
lol does it ? really? hahah i dont think so.. lol i never work on medals but still thank you...
anonymous
  • anonymous
Im spose to have 3 periods of pendulum times, I dont think i add up all my averages. i think im spose to have 3
1 Attachment
nubeer
  • nubeer
hmmm .. :( not getting you.. ok look the file you have posted and see the row average time for 10 swings what value u have in there?
anonymous
  • anonymous
yes those r the values added of the coin 1 coin 2 and coin 3
nubeer
  • nubeer
ok.. now 5 min 54 secs convert in decimal you will get 5.9 right? you did that before now divide 5.9 by 3... becasue that total time is for 3 trials.. getting it?
anonymous
  • anonymous
i get 1.966666666 = 1.97
anonymous
  • anonymous
so 1.97 would go in the period of pendulum collum???
nubeer
  • nubeer
ok.. good.. now this is average time for 10 swings.. ok? now for the time period of pendulum.. this means the time period for just 1 swing so u divide 1.97 by 10
anonymous
  • anonymous
.197
nubeer
  • nubeer
yes
anonymous
  • anonymous
Should i have 5.9, 4.9, 3.5In the average collum? Instead of the minutes and seconds or should i leave it how it is
nubeer
  • nubeer
hmm i told u these are not average.. 5.9/3 would be the aveage so 1.97 mins is the average of 10 swings.
anonymous
  • anonymous
ok thats what i was wondering lol i feel stupid but i understand it now lol
nubeer
  • nubeer
lol no worries..
anonymous
  • anonymous
ok so i fixed it take a look
1 Attachment
nubeer
  • nubeer
yup looks ok now.. this all are in mins. :)

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