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julliemyers

This may seem stupid but can anyone help?? I have to divide 10 by 5 minutes and 54 seconds????

  • one year ago
  • one year ago

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  1. julliemyers
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    @nubeer

    • one year ago
  2. ParthKohli
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    Heh, I get it.

    • one year ago
  3. ParthKohli
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    \(5 \min 54 \sec = 5 \dfrac{54}{60} = 5.9\)

    • one year ago
  4. ParthKohli
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    Is it this?

    • one year ago
  5. hba
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    @ParthKohli Yeah right.

    • one year ago
  6. julliemyers
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    Im doing a Algebra2 experiment and i have to divide my average time by 10 Here are my times 5 min 54 sec 4min 55sec 3min 30sec so when i divide these all by 10 do i put the time in decimal form? Like 5min 54 sec= 5.54??

    • one year ago
  7. ParthKohli
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    Essentially, \(5 \min 54 \sec = {5 } + \dfrac{54}{60}\) as we're expressing the seconds as a fraction.

    • one year ago
  8. ParthKohli
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    Now, you can simplify \(\dfrac{54}{60}\).

    • one year ago
  9. julliemyers
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    so, 5.9 divide by 10? and i get .59? and that would be my awsner for that one

    • one year ago
  10. ParthKohli
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    BTW, it'd be dividing 5 min 54 sec by 10, not the vice-versa.

    • one year ago
  11. ParthKohli
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    Yes, that'd be your answer :) @julliemyers

    • one year ago
  12. julliemyers
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    oh ok then so just to make sure i get the rest correct let me do them and will u check them?

    • one year ago
  13. nubeer
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    hmm it says to divide the average time by 10.. so that might not be the answer.. first you have to convert all your times into decimal

    • one year ago
  14. ParthKohli
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    Sure! =)

    • one year ago
  15. nagdy1
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    ((10/5) minute) + (54 seconds) = 2.9 minutes

    • one year ago
  16. ParthKohli
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    Oh, yes.

    • one year ago
  17. ParthKohli
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    Didn't see that question below.

    • one year ago
  18. julliemyers
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    no i had 3 trials and i have to divide 10 by indivaual times

    • one year ago
  19. nagdy1
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    serach on google divide 10 by 5 minutes and 54 seconds

    • one year ago
  20. ParthKohli
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    Okay... so can you divide the other times by 10 after converting them and take the average of all figures you get?

    • one year ago
  21. julliemyers
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    hang on ill show u my table

    • one year ago
  22. julliemyers
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    • one year ago
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  23. nagdy1
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    5 minutes 10 seconds divide it by 5 = 1 minute 2 seconds.

    • one year ago
  24. ParthKohli
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    Oh, so that is the question.

    • one year ago
  25. julliemyers
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    this is the directions . For each trial, use a stopwatch to record the number of seconds it takes for the pendulum to complete 10 full swings. Record each time in the i rst column of the table provided on the next page. Next, i nd and record the average of the three times you listed. Finally, divide the average time by 10 to determine the period of the pendulum. Repeat the procedure using two coins, then using three coins, recording the data in the second and third columns, respectively. Does it appear that the weight of the bob af ected the period of the pendulum? What factors other than the weight might af ect the period of the pendulum?

    • one year ago
  26. ParthKohli
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    So you have to find the average period. It'd be 5 min 54 sec by 10.

    • one year ago
  27. julliemyers
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    yes each collum had their own average time

    • one year ago
  28. ParthKohli
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    Then I'm afraid you'd have to complete this experiment by yourself.

    • one year ago
  29. ParthKohli
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    Did you do this experiment?

    • one year ago
  30. nubeer
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    hmm ok i have a question.. something don't seem right. in the trial 1 with 1 coin the time u have wrote is for 10 swings?

    • one year ago
  31. julliemyers
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    yes it was in the file i attatched i just needed help on how i would divide time by 10

    • one year ago
  32. ParthKohli
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    But that wouldn't be the time for 10 swings. Though there's a cheat: You can divide it by 3. ;)

    • one year ago
  33. dewron
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    add all noted times with seconds as fraction and then divide by 10. here is your answer :)

    • one year ago
  34. nubeer
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    @julliemyers wel i think the average time u have found for 10 swings in that file is wrong.. u need to check that again.

    • one year ago
  35. ParthKohli
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    You can add 3 noted times and divide by 3 -- no one would realize :D

    • one year ago
  36. ParthKohli
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    @nubeer: Seems like julliemyers has summed up the three noted times in the above rows.

    • one year ago
  37. nubeer
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    yup she did that.. she just forgot to divide by 3

    • one year ago
  38. ParthKohli
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    Mhm

    • one year ago
  39. julliemyers
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    @nubeer it doesnt say i need to divide by 3 tho?

    • one year ago
  40. nubeer
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    i know it don't say and it will never say.. the Word Average itself says it.. Average = Total time/ no. of times experiment performed.. means you would add up the time of all the 3 trials and then divide it by 3.. IF INCASE.. there was a 4th trial then you would add all the 4 times and divide by 4... you have to do this where ever the average word comes up

    • one year ago
  41. julliemyers
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    ohh Yea i remeber that. So for ex 5 min 54sec would be 5.54/3 =1.846 then i devide that by 10?? =0.1846????

    • one year ago
  42. nubeer
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    yes..

    • one year ago
  43. julliemyers
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    ok i think i have got it lol -.-

    • one year ago
  44. nubeer
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    lol good :)

    • one year ago
  45. ParthKohli
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    @julliemyers No

    • one year ago
  46. julliemyers
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    @ParthKohli No to what? Im wrong?????

    • one year ago
  47. nubeer
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    lol that was 5.9 .. the total time.

    • one year ago
  48. ParthKohli
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    It's not \(5.54\); it's \(5.9\)

    • one year ago
  49. ParthKohli
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    And you don't have to further divide by 10.

    • one year ago
  50. ParthKohli
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    Got it? :D

    • one year ago
  51. nubeer
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    lol she have to divide by 10 to find the time period.. @ParthKohli

    • one year ago
  52. julliemyers
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    Im so confused (-.-)

    • one year ago
  53. nubeer
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    First add all the time , trial 1,2,3 that would be 5.9 and divide it by 3.. the value you will get you will put that against this row "Average time complete 10 full swings"

    • one year ago
  54. ParthKohli
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    Oh yes

    • one year ago
  55. nubeer
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    Now.. the value in this row "Average time complete 10 full swings" you would divide it by 10 and put them in this row "Period of pendulum "

    • one year ago
  56. ParthKohli
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    @nubeer: My medal increased your SS :P

    • one year ago
  57. nubeer
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    lol does it ? really? hahah i dont think so.. lol i never work on medals but still thank you...

    • one year ago
  58. julliemyers
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    Im spose to have 3 periods of pendulum times, I dont think i add up all my averages. i think im spose to have 3

    • one year ago
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  59. nubeer
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    hmmm .. :( not getting you.. ok look the file you have posted and see the row average time for 10 swings what value u have in there?

    • one year ago
  60. julliemyers
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    yes those r the values added of the coin 1 coin 2 and coin 3

    • one year ago
  61. nubeer
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    ok.. now 5 min 54 secs convert in decimal you will get 5.9 right? you did that before now divide 5.9 by 3... becasue that total time is for 3 trials.. getting it?

    • one year ago
  62. julliemyers
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    i get 1.966666666 = 1.97

    • one year ago
  63. julliemyers
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    so 1.97 would go in the period of pendulum collum???

    • one year ago
  64. nubeer
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    ok.. good.. now this is average time for 10 swings.. ok? now for the time period of pendulum.. this means the time period for just 1 swing so u divide 1.97 by 10

    • one year ago
  65. julliemyers
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    .197

    • one year ago
  66. nubeer
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    yes

    • one year ago
  67. julliemyers
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    Should i have 5.9, 4.9, 3.5In the average collum? Instead of the minutes and seconds or should i leave it how it is

    • one year ago
  68. nubeer
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    hmm i told u these are not average.. 5.9/3 would be the aveage so 1.97 mins is the average of 10 swings.

    • one year ago
  69. julliemyers
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    ok thats what i was wondering lol i feel stupid but i understand it now lol

    • one year ago
  70. nubeer
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    lol no worries..

    • one year ago
  71. julliemyers
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    ok so i fixed it take a look

    • one year ago
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  72. nubeer
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    yup looks ok now.. this all are in mins. :)

    • one year ago
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