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algebra2sucks

Simplify each expression. Rationalize denominators. Show all work, step-by-step. sqrt w^4/x^3

  • one year ago
  • one year ago

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  1. alrightatmaths
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    Is the bottom a sqrt too?

    • one year ago
  2. alrightatmaths
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    If so, multiply top and bottom by sqrt x^3

    • one year ago
  3. algebra2sucks
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    this is what it looks like

    • one year ago
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  4. alrightatmaths
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    Right well that is the same as \[\sqrt{w^4}/\sqrt{x^3}\] So just multiply the top and the bottom by \[\sqrt{x^3}\] giving you x^3 on the bottom and \[\sqrt{w^4}\sqrt{x}\] on the top

    • one year ago
  5. algebra2sucks
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    thats it or more to it

    • one year ago
  6. algebra2sucks
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    help @tcarroll010

    • one year ago
  7. alrightatmaths
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    Multiply the fraction by root x^3 over root x^3

    • one year ago
  8. alrightatmaths
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    \[\frac{ \sqrt{w^4}\sqrt{x^3} }{ x^3 }\]

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  9. alrightatmaths
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    And sqrt of w^4 is just w^2 so \[\frac{ w^2\sqrt{x^3} }{ x^3 }\]

    • one year ago
  10. alrightatmaths
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    That's it.

    • one year ago
  11. algebra2sucks
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    thank u!!

    • one year ago
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