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chakshu
 2 years ago
double integral of e^y/x dy dx with outer limits as 0 and 2 and inner limits as 0 and x^2 ???
chakshu
 2 years ago
double integral of e^y/x dy dx with outer limits as 0 and 2 and inner limits as 0 and x^2 ???

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chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0@TuringTest why do we dont change order in this one...ans, is 1/2

chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{1}\int\limits_{0}^{x^2} e^ y/x dy dx\]

chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0@ kainui then why we change order here let me tag you in one...

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1I'm sorry, I'm either really tired or confused. It seems to me that this integral can only be done by changing the bounds. Is that what you are saying @chakshu ? You are asking why we have to change the bonds?

chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0m asking that why this question is not solved by changing order of integeration its just solved simply to give ans. as 1/2

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0i will repeat turing's word. in last Q, it was difficult to integrate w.r.t y after x was integrated, thats why bounds were changed. in this case, its easy to integrate without changing bounds

chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/users/chakshu#/updates/5080305ee4b0b56960054f2d this is another questn that involves changing order i just wanna knoe the theoritical differnce that when do we have to change order to integerate ????hope this is simple to understnd

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.0It might help to sketch a picture of the graph first to better explain this.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1i may be totally wrong (probably am) but isn't \[\int_0^{x^2}\frac{e^y}{x}dy=\frac{e^{x^2}1}{x}\]

chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0@hartnn so ur sayin since in previous questn we had difficult limts so we changed order and in this one we have easy limits so we dont??

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1then second job would be to compute \[\int_0^1\frac{e^{x^2}1}{x}dx\]

chakshu
 2 years ago
Best ResponseYou've already chosen the best response.0ohhhhhhhh my bad frnds its e^y/x sorrrrrrrrryyyyyy for that mistake

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0its not about limits, its about what u get after integrating w.r.t one of the variables, sometimes the resulting function is very difficult to integrate w.r.t other variable...

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.0In general: \[\int\limits \int\limits f(x,y)dA = \int\limits_{a}^{b} \int\limits_{g_1(x)}^{g_2(x)}f(x,y)dydx \]

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.0Use parentheses. e^(y/x) or (e^y)/x?

Kainui
 2 years ago
Best ResponseYou've already chosen the best response.0@chakshu no one can help you until you answer this last question I just asked you lol.

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1I answered his question through facebook everyone, my connect here sucks it was e^(y/x)
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