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chakshu

  • 2 years ago

double integral of e^y/x dy dx with outer limits as 0 and 2 and inner limits as 0 and x^2 ???

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  1. chakshu
    • 2 years ago
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    @TuringTest why do we dont change order in this one...ans, is 1/2

  2. chakshu
    • 2 years ago
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    \[\int\limits_{0}^{1}\int\limits_{0}^{x^2} e^ y/x dy dx\]

  3. chakshu
    • 2 years ago
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    @ kainui then why we change order here let me tag you in one...

  4. TuringTest
    • 2 years ago
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    I'm sorry, I'm either really tired or confused. It seems to me that this integral can only be done by changing the bounds. Is that what you are saying @chakshu ? You are asking why we have to change the bonds?

  5. chakshu
    • 2 years ago
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    m asking that why this question is not solved by changing order of integeration its just solved simply to give ans. as 1/2

  6. hartnn
    • 2 years ago
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    i will repeat turing's word. in last Q, it was difficult to integrate w.r.t y after x was integrated, thats why bounds were changed. in this case, its easy to integrate without changing bounds

  7. chakshu
    • 2 years ago
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    http://openstudy.com/users/chakshu#/updates/5080305ee4b0b56960054f2d this is another questn that involves changing order i just wanna knoe the theoritical differnce that when do we have to change order to integerate ????hope this is simple to understnd

  8. abb0t
    • 2 years ago
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    It might help to sketch a picture of the graph first to better explain this.

  9. satellite73
    • 2 years ago
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    i may be totally wrong (probably am) but isn't \[\int_0^{x^2}\frac{e^y}{x}dy=\frac{e^{x^2}-1}{x}\]

  10. chakshu
    • 2 years ago
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    @hartnn so ur sayin since in previous questn we had difficult limts so we changed order and in this one we have easy limits so we dont??

  11. satellite73
    • 2 years ago
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    then second job would be to compute \[\int_0^1\frac{e^{x^2}-1}{x}dx\]

  12. chakshu
    • 2 years ago
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    ohhhhhhhh my bad frnds its e^y/x sorrrrrrrrryyyyyy for that mistake

  13. hartnn
    • 2 years ago
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    its not about limits, its about what u get after integrating w.r.t one of the variables, sometimes the resulting function is very difficult to integrate w.r.t other variable...

  14. abb0t
    • 2 years ago
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    In general: \[\int\limits \int\limits f(x,y)dA = \int\limits_{a}^{b} \int\limits_{g_1(x)}^{g_2(x)}f(x,y)dydx \]

  15. Kainui
    • 2 years ago
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    Use parentheses. e^(y/x) or (e^y)/x?

  16. Kainui
    • 2 years ago
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    @chakshu no one can help you until you answer this last question I just asked you lol.

  17. TuringTest
    • 2 years ago
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    I answered his question through facebook everyone, my connect here sucks it was e^(y/x)

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