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anonymous
 3 years ago
Solve the system, using substitution. Write the solution as an ordered pair.
x = 2y  2 and 3x  y = 14
(6, 4)
(4, 6)
(1, 0)
(0, 1)
no solution
anonymous
 3 years ago
Solve the system, using substitution. Write the solution as an ordered pair. x = 2y  2 and 3x  y = 14 (6, 4) (4, 6) (1, 0) (0, 1) no solution

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ans is (6,4)? correct?

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0Substitute your x = 2y2 for x in the second equation. and solve for y.

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0Once you have your y, plug in that value back for the first equation to get your x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.03(2y  2)  y = 14 5y6 = 14 y=4 => x=6 (6,4)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how did you get 5y? it would be 6y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes but them you have a y, so 5y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05y6=14 i get that but what did you do after that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05y = 14+6 5y = 20 y=4 them from 3x  y = 14 3x  (4) = 14 3x = 18 x=6 so (6,4)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok thank you i get it:)
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