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Ok

|dw:1356272011895:dw|

Find a common denominator

x^2+6?

I think you need to either review the distributive property or learn FOIL method

\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\] use \(a=8,b=x+2,c=4,d=x+3\)

use parentheses and make a direct substitution

wait so i cross multiply?

do i combine the denominators?

well to get a final answer i would need to use \[x ^{2}5x+6\] wouldnt I?

so 8x+24 + 4x+8 = 12x+32 ?

your numerator is correct, i would be \(12x+3
2\)

and your denominator is \(x^2+5x+6\)

would i have any restrictions?

so it cant be the 2 and 3 from the original denominators?

it cannot be \(-2\)

one denominator is \(x+2\) so if \(x=-2\) then you get \(-2+2=0\) and the denominator cannot be 0

ok that makes sense thanks :)

yw