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sha0403

  • 3 years ago

a school has 63 students studying A,B and C. 33 study A, 25 study B, 26 study C. 10 study A and B, 9 study B and C while 8 study both A and C. Equal num study all three subjects as those who learn none of the three. How many study all 3 subjects? #help me solve this question#

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  1. Aditi_Singh
    • 3 years ago
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    |dw:1356287630536:dw| a+b+d+e = 33 b+e+f+c = 25 d+e+f+g = 26 b+e = 10 f+e = 9 d+e = 8 e = 63 - (a+b+c+d) Solve for e..

  2. sha0403
    • 3 years ago
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    where do you get e=63-(a+b+c+d)?

  3. Aditi_Singh
    • 3 years ago
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    It is given that - Equal num study all three subjects as those who learn none of the three. The people who do not study any of them are given by U - (A U B) Here, U = 63 .. And, A U B is given be (a+b+c+d+e) and, I considered the people who study all the three as 'e' And, Sorry, I did a mistake .. I would be -> e = 63 - (a+b+c+d+e)

  4. sha0403
    • 3 years ago
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    why u no include f in e=63-(a+b+c+d+e)? can u explain me? i still not understand....

  5. hartnn
    • 3 years ago
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    those who learn none of the three subject ----> 63-(a+b+c+d+e+f+g)

  6. hartnn
    • 3 years ago
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    right ?

  7. hartnn
    • 3 years ago
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    e= 63-(a+b+c+d+e+f+g)

  8. sha0403
    • 3 years ago
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    i don't know but the answer is 3..

  9. Aditi_Singh
    • 3 years ago
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    pellet! :P I'm extremely sorry again! :P yeah, you are absolutely correct! - it ought to be 63 - (a+b+c+d+e+f+g)

  10. hartnn
    • 3 years ago
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    those who learn none of the three subject = total students - students learning atleast 1 subject, got this ?

  11. hartnn
    • 3 years ago
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    those who learn none of the three subject = U - (A U B U C) = 63-(a+b+c+d+e+f+g)

  12. hartnn
    • 3 years ago
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    so now did u get how e=63-(a+b+c+d+e+f+g) @sha0403 ?

  13. sha0403
    • 3 years ago
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    ook thank u so much u all for helping me...now i get it... ;)

  14. hartnn
    • 3 years ago
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    good :) welcome ^_^

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