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@algebra2sucks
Is it neccessary that you use the pythogras theorm :)

Well it is easy to use the Pythagoras theorm
\[H^2=B^2+P^2\]
Where,
\[B=2\sqrt{3}\]\[P=\sqrt{3}\]

Just put in the values and find H

We have to take it out of sqrt right?
So it would be B = 2 1.7
P = 1.7???

No i have shown you the formula just put in the values and solve it.

Im not sure how to do that

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