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algebra2sucks

Find the length of the hypotenuse. Show all work. HINT: Use the Pythagorean Theorem.

  • one year ago
  • one year ago

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  1. algebra2sucks
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    • one year ago
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  2. hba
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    @algebra2sucks Is it neccessary that you use the pythogras theorm :)

    • one year ago
  3. hba
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    Well it is easy to use the Pythagoras theorm \[H^2=B^2+P^2\] Where, \[B=2\sqrt{3}\]\[P=\sqrt{3}\]

    • one year ago
  4. algebra2sucks
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    Yes i think it is @hba so what do i do

    • one year ago
  5. hba
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    Just put in the values and find H

    • one year ago
  6. algebra2sucks
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    We have to take it out of sqrt right? So it would be B = 2 1.7 P = 1.7???

    • one year ago
  7. hba
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    No i have shown you the formula just put in the values and solve it.

    • one year ago
  8. algebra2sucks
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    Im not sure how to do that

    • one year ago
  9. precal
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    |dw:1356291834762:dw|

    • one year ago
  10. algebra2sucks
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    thanks @precal

    • one year ago
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