algebra2sucks
Find the length of the hypotenuse. Show all work.
HINT: Use the Pythagorean Theorem.



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algebra2sucks
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hba
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@algebra2sucks
Is it neccessary that you use the pythogras theorm :)

hba
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Well it is easy to use the Pythagoras theorm
\[H^2=B^2+P^2\]
Where,
\[B=2\sqrt{3}\]\[P=\sqrt{3}\]

algebra2sucks
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Yes i think it is @hba
so what do i do

hba
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Just put in the values and find H

algebra2sucks
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We have to take it out of sqrt right?
So it would be B = 2 1.7
P = 1.7???

hba
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No i have shown you the formula just put in the values and solve it.

algebra2sucks
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Im not sure how to do that

precal
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dw:1356291834762:dw

algebra2sucks
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thanks @precal