A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
i have no clue how to solve this
anonymous
 3 years ago
i have no clue how to solve this

This Question is Closed

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3\[\frac{ g+3 }{ 4f^3 }\times \frac{ 6f }{ 8g+24 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would i cross multiply?

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3no. just simplify n multiply

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know how i would simplify that my teacher never explained it

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3\[\frac{ g+3 }{ 4f^3 }\times \frac{ 6f }{ 8(g+3) }\] you can cancel out the (g+3). remember: \[\frac{ T }{ T } = 1\] the same thing with: \[\frac{ 2a^{10} }{ 4a^{11} } = \frac{ 1 }{ 2a }\] I basically simplified 2/4 and the a's were subtracted \[\frac{ a^{10} }{ a^{11} } = (1011 = 1) = a^{1} = \frac{ 1 }{ a^1 }= \frac{ 1 }{ }\]

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3Appy that to your problem and you should get an answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[4f ^{2}* \frac{ 6f }{ 8 }\]?

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3Yes. But now your answer is: \[\frac{ 6f }{ 4f^2(8) }\] can you simplify that answer more?

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3You actually can. Oh and I made a mistake, i didn't provide you the correct answer with that last one. It should actually be: \[\frac{ 6 }{ 32f^2 }\] and that CAN be simplified furhter to: \[\frac{ 3 }{ 16f^2 }\] this is because you can divide 6 and 32 by 2. 2 is the common number between them. It works the same as I explained before: \[\frac{ 3 \times 2 }{ (16 \times 2) f^2 }= (\frac{ 3 }{ 16 })(\frac{ 2 }{ 2 })(\frac{ 1 }{ f^2 })\] and remember: \[\frac{ 2 }{ 2 } = 1\] and 1 multiplied by anything is simply the number or letter itself.

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.3The answer you provided: \[(\frac{ 1 }{ 4f^2 })(\frac{ 6f }{ 8 }) \] is half right. I'm not sure if you just messed up bu accident, but just wanted to clarify incase you didn't notice and where I got my final correct answer from.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok thank you so much !! = )
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.