A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

In session 8, the professor offers a geometric/visual proof of the fact that lim of sin(x)/x as x goes to 0 = 1. I think I'm missing some basic trig. At one point he mentions that the length of the right side of the triangle (the one next to the arc) is equal to sin(theta). I don't get how that's possible. If sin = opposite/hypotenuse, then how could the length of that opposite side be the same length as the ratio of o/h? Is it simply because of the fact that the radius is 1, so the hypotenuse is 1 and since sin(theta) = o/h its just o/1 so therefore the opposite is = sin(theta)? Which also explains why the arc length is equal to theta? Meaning, since we have radius of 1, and the angle theta is equal to arc length/r and r is 1, so then solving for arc length we have an equation of arc length = theta * r = theta?

  • This Question is Closed

    Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.