Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

funinaboxBest ResponseYou've already chosen the best response.0
what exactly is the question
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
i dont know how to do the problem, and i want someone to walk me throught the steps so i can understand the futture questions. 4x^2+8136x
 one year ago

HeroBest ResponseYou've already chosen the best response.1
When factoring any quadratic, the goal is always the same. Find two numbers (x and y) that add to get b, but multiply to get ac. x + y = b xy = ac
 one year ago

HeroBest ResponseYou've already chosen the best response.1
In this case, we need to find: x + y = 36 xy = 324
 one year ago

HeroBest ResponseYou've already chosen the best response.1
The only two numbers that work is x = 18 y = 18
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Anytime both x and y are the same, it means you will have a perfect square.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
4x^2  36x + 81 4x^2  18x  18x + 81 2x(2x  9)  9(2x  9) (2x  9)(2x  9) (2x  9)^2
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
alright. so how about 4y^2 +16y+16 How would that work..
 one year ago

HeroBest ResponseYou've already chosen the best response.1
It works the same way: x + y = 16 xy = 64 Find x and y
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I'm pretty sure you can find the two numbers
 one year ago

HeroBest ResponseYou've already chosen the best response.1
It doesn't require doing any actual Algebra. All you do is ask yourself, "What two numbers add to get 16, yet multiply to get 64?".
 one year ago

HeroBest ResponseYou've already chosen the best response.1
In this case, the two numbers are the same.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I'm not going to your homework for you. I'll show you how to do one problem. But, don't think I'm going to show you how to do every single problem. You need to figure this one out. The steps are exactly the same as the previous problem.
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
i dont expect you to do it for me lol. i actually need to learn it. im not in hs like a bunch of the people on there. i am in nursing school and personally do not want to have to repay for the class.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Okay, so did you find the two numbers yet?
 one year ago

funinaboxBest ResponseYou've already chosen the best response.0
if you are having trouble, a simple way of solving this is substitution. x + y = 16 xy = 64 or in other words y = 16  x x(16  x) = 64 further simplified... 16x  x^2 = 64 x^2  16x + 64 = 0 then you can factor and solve
 one year ago

funinaboxBest ResponseYou've already chosen the best response.0
which is a much more simple polynomial to answer than the previous one
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Funny thing is, she would still need to find the same two numbers either way.
 one year ago

funinaboxBest ResponseYou've already chosen the best response.0
i know i realized that after i posted it :D but it's still a more simple polynomial to look at, at least in terms of coefficients
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
ok. i think i got it.
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
4y^2 + 16y +16 4(y^2 + 4y + 4) 4(y^2+ 2y + 2y+ 2) 4 [y(y+2) + 2(y+2)] =4(y+2)^2
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
right? yes no? lol ive always been terrible with numbers :/
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
sheesh. glad i dont ddeal with this in my profession ha
 one year ago

HeroBest ResponseYou've already chosen the best response.1
You have to think of math as "playing with numbers", rather than "a chore".
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
its just too difficult for me to understand. anyting else you can put in front of me and i get it right away, and sure certain parts of math i can too, but when it comes to this i just...ugggg. wanna curl up in a ball and cry
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Most of the time, students that don't get it are usually those who are not very good with seeing the relationships between addition and multiplication. Either that or they don't have their multiplication tables well memorized.
 one year ago

HeroBest ResponseYou've already chosen the best response.1
This concept is definitely more "mental math" compared to other algebra concepts.
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
my tables are fine...and maybe i do have a problem with my adding and multiplying and i just dont realize it? cuz ive never gotten the factoring polynomials things. not now, not in hs
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
hey. only gotta deal with this until march so i think i can stick it out
 one year ago

HeroBest ResponseYou've already chosen the best response.1
If you have difficulty with "finding the two numbers that add to get one number, but multiply to get another", then your problem is not with factoring, but with the multiplication/addition relationships.
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
yeah. thats what i thought.
 one year ago

kdarnell08Best ResponseYou've already chosen the best response.1
well thank you! i appreciate it very much!! back to other homework. Happy Holidays!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.