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anonymous
 3 years ago
How about 4x^2 + 81 36x
anonymous
 3 years ago
How about 4x^2 + 81 36x

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what exactly is the question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont know how to do the problem, and i want someone to walk me throught the steps so i can understand the futture questions. 4x^2+8136x

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1When factoring any quadratic, the goal is always the same. Find two numbers (x and y) that add to get b, but multiply to get ac. x + y = b xy = ac

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1In this case, we need to find: x + y = 36 xy = 324

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1The only two numbers that work is x = 18 y = 18

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Anytime both x and y are the same, it means you will have a perfect square.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.14x^2  36x + 81 4x^2  18x  18x + 81 2x(2x  9)  9(2x  9) (2x  9)(2x  9) (2x  9)^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0alright. so how about 4y^2 +16y+16 How would that work..

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1It works the same way: x + y = 16 xy = 64 Find x and y

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1I'm pretty sure you can find the two numbers

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1It doesn't require doing any actual Algebra. All you do is ask yourself, "What two numbers add to get 16, yet multiply to get 64?".

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1In this case, the two numbers are the same.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1I'm not going to your homework for you. I'll show you how to do one problem. But, don't think I'm going to show you how to do every single problem. You need to figure this one out. The steps are exactly the same as the previous problem.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont expect you to do it for me lol. i actually need to learn it. im not in hs like a bunch of the people on there. i am in nursing school and personally do not want to have to repay for the class.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Okay, so did you find the two numbers yet?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you are having trouble, a simple way of solving this is substitution. x + y = 16 xy = 64 or in other words y = 16  x x(16  x) = 64 further simplified... 16x  x^2 = 64 x^2  16x + 64 = 0 then you can factor and solve

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which is a much more simple polynomial to answer than the previous one

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Funny thing is, she would still need to find the same two numbers either way.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know i realized that after i posted it :D but it's still a more simple polynomial to look at, at least in terms of coefficients

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok. i think i got it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04y^2 + 16y +16 4(y^2 + 4y + 4) 4(y^2+ 2y + 2y+ 2) 4 [y(y+2) + 2(y+2)] =4(y+2)^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right? yes no? lol ive always been terrible with numbers :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sheesh. glad i dont ddeal with this in my profession ha

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1You have to think of math as "playing with numbers", rather than "a chore".

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its just too difficult for me to understand. anyting else you can put in front of me and i get it right away, and sure certain parts of math i can too, but when it comes to this i just...ugggg. wanna curl up in a ball and cry

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Most of the time, students that don't get it are usually those who are not very good with seeing the relationships between addition and multiplication. Either that or they don't have their multiplication tables well memorized.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1This concept is definitely more "mental math" compared to other algebra concepts.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my tables are fine...and maybe i do have a problem with my adding and multiplying and i just dont realize it? cuz ive never gotten the factoring polynomials things. not now, not in hs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hey. only gotta deal with this until march so i think i can stick it out

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1If you have difficulty with "finding the two numbers that add to get one number, but multiply to get another", then your problem is not with factoring, but with the multiplication/addition relationships.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah. thats what i thought.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well thank you! i appreciate it very much!! back to other homework. Happy Holidays!
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