Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Related rates (parametric derivatives)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

if y=3x^2+2x and dx/dt=4, find dy/dt when x=3 My answer: dy/dt=24x+8; dy/dt=80. Can someone please check this? THanks!
isn't it dy/dt = 6x dx/dt + 2dx/dt ? can someone check this ?
:S

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Yah @tamtoan is on the right track there,\[\huge y=3x^2+2x\]If we take the derivative with respect to TIME, we'll get,\[\huge \color{#CC0033}{\frac{dy}{dt}}=6x\color{#F35633}{\frac{dx}{dt}}+2\color{#F35633}{\frac{dx}{dt}}\]And they gave us information about dx/dt and x.\[\huge \color{#CC0033}{\frac{dy}{dt}}=6(3)(\color{#F35633}{4})+2(\color{#F35633}{4})\]Understand where those numbers are coming from?
Uh, the answer is defienitely 80, because I just submitted te assignment. Let me go over what happened though
Yeah, @zepdrix , you have the dx/dt because x is a function of t; @tamtoan didn't have that. Thanks.
Tam had the same thing, he just didn't plug in the x and dx/dt values for you :D
Oh he did :S. Well, thanks for helping out!

Not the answer you are looking for?

Search for more explanations.

Ask your own question