An Air Column of 12cm lenght is trapped by a mercury column of 16cm long in a cappillary tube of uniform bore what would the lenght of the air column when the tube is kept vertically with its open end down?
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The atmospheric pressure is equivalent to 76 cm of Hg column.
Initially when it was kept upright -
The upward pressure due to the air column of 12 cm length(say p1)= Atmospheric pressure + pressure due to the mercury column
So, p1 = 76 + 16 = 92cm of Hg column.
When it is flipped over-
Atmospheric pressure = pressure due to mercury column+ pressure due to the air column of unknown length(say p2)
that gives, p2=60cm Hg
Initial volume(v1)=12*A where A is area of the capillary tube
Final volume(v2)=x*A where x is the final length of the air column
which gives x=18.4cm
@Diwakar the options are 9.9cm 13.8cm 14.6cm 15.2cm
I took the tube to be standing vertically with its mouth above in the previous solution.
If we took the tube to be lying horizontally in the initial case, the pressure due to the air column would have been equal to atmospheric pressure = 76cm
The final presasure would have been the same=92cm
Application of Boyle's law now would give us x=15.2cm.