anonymous
  • anonymous
A+B = 5 pie/4, ( (1+cotA) ( 1 + cotB) )/(cotAcotB) = ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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hartnn
  • hartnn
( (1+cotA) ( 1 + cotB) )/(cotAcotB) = (1+cot A + cot B + cot A cot B) / cotA cot B now separate the denominator.
anonymous
  • anonymous
tanAtanB + TanA + tanB + 1
hartnn
  • hartnn
what ?

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hartnn
  • hartnn
= (1+cot A + cot B)/cotAcot B + (cot A cot B) / cotA cot B = (1+cot A + cot B)/cotAcot B + 1
hartnn
  • hartnn
that '1' will be a trouble...
hartnn
  • hartnn
cot (A+B) =.... ?
hartnn
  • hartnn
ok, lets work with tan tan(A+B) = tan 5pi/4 = ... ?
anonymous
  • anonymous
tan 5pi/4=1
hartnn
  • hartnn
tan(A+B) = (tan A+tan B) /(1+tan A. tan B) = ...
anonymous
  • anonymous
tan(A+B) = (tan A+tan B) /(1-tan A. tan B)
hartnn
  • hartnn
oops, tan(A+B) = (tan A+tan B) /(1-tan A. tan B) =1 which gives tan A+tan B = 1-tan A tan B
hartnn
  • hartnn
so, tanAtanB + TanA + tanB + 1=...?
hartnn
  • hartnn
tanAtanB + TanA + tanB + 1= tanAtanB +1-tan Atan B+ 1=2
anonymous
  • anonymous
Yup... thxx...

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