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anonymous
 4 years ago
A+B = 5 pie/4, ( (1+cotA) ( 1 + cotB) )/(cotAcotB) = ?
anonymous
 4 years ago
A+B = 5 pie/4, ( (1+cotA) ( 1 + cotB) )/(cotAcotB) = ?

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hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2( (1+cotA) ( 1 + cotB) )/(cotAcotB) = (1+cot A + cot B + cot A cot B) / cotA cot B now separate the denominator.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tanAtanB + TanA + tanB + 1

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2= (1+cot A + cot B)/cotAcot B + (cot A cot B) / cotA cot B = (1+cot A + cot B)/cotAcot B + 1

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2that '1' will be a trouble...

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2ok, lets work with tan tan(A+B) = tan 5pi/4 = ... ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2tan(A+B) = (tan A+tan B) /(1+tan A. tan B) = ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tan(A+B) = (tan A+tan B) /(1tan A. tan B)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2oops, tan(A+B) = (tan A+tan B) /(1tan A. tan B) =1 which gives tan A+tan B = 1tan A tan B

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2so, tanAtanB + TanA + tanB + 1=...?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2tanAtanB + TanA + tanB + 1= tanAtanB +1tan Atan B+ 1=2
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