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ilovenyc
 3 years ago
Solve 2x + 1 less than or greater to 7 and describe the graph of the solution.
A x less than or greater to 4; closed circle on 4, shading to the left
B x greater than or equal to 4; closed circle on 4, shading to the right
C x greater than or equal to 4; open circle on 4, shading to the right
D x less than or greater to 4; open circle on 4, shading to the left
ilovenyc
 3 years ago
Solve 2x + 1 less than or greater to 7 and describe the graph of the solution. A x less than or greater to 4; closed circle on 4, shading to the left B x greater than or equal to 4; closed circle on 4, shading to the right C x greater than or equal to 4; open circle on 4, shading to the right D x less than or greater to 4; open circle on 4, shading to the left

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Stiwan
 3 years ago
Best ResponseYou've already chosen the best response.1I'll look at the cases separately (though they're very similar):  2x +1 < 7  1 2x < 8  : (4) x > 4 (< becomes > when multiplying with a negative number) That means if 2x +1 < 7 is true, it follows that x is greater than 4. 2x+1 > 7  1 2x > 8  :(4) x < 4 (> becomes < when multiplying with a negative number) That means if 2x +1 > 7 is ture, it follows that x is smaller than 4. Hence, the inequality is true if x is not 4. This means that your solution is anything except 4. I'm not quite sure what you mean by "closed/open" circle or "shading to the left", but if it means what I think it means then it is an open circle. I have no idea what "shading to the left" means. Sorry, English is not my native language.

Stiwan
 3 years ago
Best ResponseYou've already chosen the best response.1But anyway, I'm quite sure that the right answer is D
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