anonymous
  • anonymous
Solve -2x + 1 less than or greater to -7 and describe the graph of the solution. A x less than or greater to 4; closed circle on 4, shading to the left B x greater than or equal to 4; closed circle on 4, shading to the right C x greater than or equal to 4; open circle on 4, shading to the right D x less than or greater to 4; open circle on 4, shading to the left
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I'll look at the cases separately (though they're very similar): - 2x +1 < -7 | -1 -2x < -8 | : (-4) x > 4 (< becomes > when multiplying with a negative number) That means if -2x +1 < -7 is true, it follows that x is greater than 4. -2x+1 > -7 | -1 -2x > -8 | :(-4) x < 4 (> becomes < when multiplying with a negative number) That means if -2x +1 > -7 is ture, it follows that x is smaller than 4. Hence, the inequality is true if x is not 4. This means that your solution is anything except 4. I'm not quite sure what you mean by "closed/open" circle or "shading to the left", but if it means what I think it means then it is an open circle. I have no idea what "shading to the left" means. Sorry, English is not my native language.
anonymous
  • anonymous
But anyway, I'm quite sure that the right answer is D
anonymous
  • anonymous
@Stiwan thank you!

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