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Solve 2x + 1 less than or greater to 7 and describe the graph of the solution.
A x less than or greater to 4; closed circle on 4, shading to the left
B x greater than or equal to 4; closed circle on 4, shading to the right
C x greater than or equal to 4; open circle on 4, shading to the right
D x less than or greater to 4; open circle on 4, shading to the left
 one year ago
 one year ago
Solve 2x + 1 less than or greater to 7 and describe the graph of the solution. A x less than or greater to 4; closed circle on 4, shading to the left B x greater than or equal to 4; closed circle on 4, shading to the right C x greater than or equal to 4; open circle on 4, shading to the right D x less than or greater to 4; open circle on 4, shading to the left
 one year ago
 one year ago

This Question is Closed

StiwanBest ResponseYou've already chosen the best response.1
I'll look at the cases separately (though they're very similar):  2x +1 < 7  1 2x < 8  : (4) x > 4 (< becomes > when multiplying with a negative number) That means if 2x +1 < 7 is true, it follows that x is greater than 4. 2x+1 > 7  1 2x > 8  :(4) x < 4 (> becomes < when multiplying with a negative number) That means if 2x +1 > 7 is ture, it follows that x is smaller than 4. Hence, the inequality is true if x is not 4. This means that your solution is anything except 4. I'm not quite sure what you mean by "closed/open" circle or "shading to the left", but if it means what I think it means then it is an open circle. I have no idea what "shading to the left" means. Sorry, English is not my native language.
 one year ago

StiwanBest ResponseYou've already chosen the best response.1
But anyway, I'm quite sure that the right answer is D
 one year ago
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