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anonymous
 3 years ago
A ball is rolled over a level lawn with initial velocity 8ms^1. due to the friction the velocity decreases and is given by dv/dt=2. Find the equation of distance travelled?
anonymous
 3 years ago
A ball is rolled over a level lawn with initial velocity 8ms^1. due to the friction the velocity decreases and is given by dv/dt=2. Find the equation of distance travelled?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0First integrate dv/dt =2 so it becomes v = 2t +C, at t =0, v=8, plug in, find C then that's the equation of velocity. then integrate velocity equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, what the meaning of equation of distance travelled? add the equation we get or what?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's the equation of distance travel in term of t, like s(t)= ...., and when you integrate velocity equation, you get distance equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, s(t) = t^2 +8t +C

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And I think at time t=0, the distance travel is 0, so 0= 0+0 +C, so C=0 s(t) = t^2 +8t is distance equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0does this answer your question ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why we must integrate the velocity equation again?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0At first, you're given dv/dt, which is the derivative of velocity, or acceleration. After you integrate it, it becomes velocity equation, which is v(t) = 2t +8. THen you integrate again to get position equation or distance travel.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oo i understand now..k tq.. :)
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