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sha0403
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A ball is rolled over a level lawn with initial velocity 8ms^1. due to the friction the velocity decreases and is given by dv/dt=2. Find the equation of distance travelled?
 one year ago
 one year ago
sha0403 Group Title
A ball is rolled over a level lawn with initial velocity 8ms^1. due to the friction the velocity decreases and is given by dv/dt=2. Find the equation of distance travelled?
 one year ago
 one year ago

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hieuvo Group TitleBest ResponseYou've already chosen the best response.3
First integrate dv/dt =2 so it becomes v = 2t +C, at t =0, v=8, plug in, find C then that's the equation of velocity. then integrate velocity equation
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
so, what the meaning of equation of distance travelled? add the equation we get or what?
 one year ago

hieuvo Group TitleBest ResponseYou've already chosen the best response.3
it's the equation of distance travel in term of t, like s(t)= ...., and when you integrate velocity equation, you get distance equation
 one year ago

hieuvo Group TitleBest ResponseYou've already chosen the best response.3
So, s(t) = t^2 +8t +C
 one year ago

hieuvo Group TitleBest ResponseYou've already chosen the best response.3
And I think at time t=0, the distance travel is 0, so 0= 0+0 +C, so C=0 s(t) = t^2 +8t is distance equation
 one year ago

hieuvo Group TitleBest ResponseYou've already chosen the best response.3
does this answer your question ?
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
why we must integrate the velocity equation again?
 one year ago

hieuvo Group TitleBest ResponseYou've already chosen the best response.3
At first, you're given dv/dt, which is the derivative of velocity, or acceleration. After you integrate it, it becomes velocity equation, which is v(t) = 2t +8. THen you integrate again to get position equation or distance travel.
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
oo i understand now..k tq.. :)
 one year ago
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