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sha0403

  • one year ago

A ball is rolled over a level lawn with initial velocity 8ms^-1. due to the friction the velocity decreases and is given by dv/dt=-2. Find the equation of distance travelled?

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  1. hieuvo
    • one year ago
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    First integrate dv/dt =-2 so it becomes v = -2t +C, at t =0, v=8, plug in, find C then that's the equation of velocity. then integrate velocity equation

  2. sha0403
    • one year ago
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    so, what the meaning of equation of distance travelled? add the equation we get or what?

  3. hieuvo
    • one year ago
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    it's the equation of distance travel in term of t, like s(t)= ...., and when you integrate velocity equation, you get distance equation

  4. hieuvo
    • one year ago
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    So, s(t) = -t^2 +8t +C

  5. hieuvo
    • one year ago
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    And I think at time t=0, the distance travel is 0, so 0= 0+0 +C, so C=0 s(t) = -t^2 +8t is distance equation

  6. hieuvo
    • one year ago
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    does this answer your question ?

  7. sha0403
    • one year ago
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    why we must integrate the velocity equation again?

  8. hieuvo
    • one year ago
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    At first, you're given dv/dt, which is the derivative of velocity, or acceleration. After you integrate it, it becomes velocity equation, which is v(t) = -2t +8. THen you integrate again to get position equation or distance travel.

  9. sha0403
    • one year ago
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    oo i understand now..k tq.. :)

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