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minnie123

  • 2 years ago

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  1. minnie123
    • 2 years ago
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  2. wio
    • 2 years ago
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    So \(x \in \{1, 2, 3\}\) and \(y\in \{1, 2, 3, 4, 5, 6, 7\}\). You want to find every pair that fits the equality \(2x+y=7\).

  3. wio
    • 2 years ago
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    I would start by making \(y\) a function of \(x\). So we have \(y(x) = -2x+7\). I would then plug in each possible \(x\).

  4. wio
    • 2 years ago
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    \[ x=1 \implies y = 5 \\ x=2 \implies y = 3 \\ x=3 \implies y = 1 \]So the answers we get is: \[F = \{(1, 5), (2,3), (3,1)\}\]

  5. wio
    • 2 years ago
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    A general heuristic I can see being useful is to make the larger set be a function of the smaller set, because you have to do less plugging stuff in.

  6. minnie123
    • 2 years ago
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    Okay thanks my internet connection sucks so it took me long to see this and respond to you... :)

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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