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katlin95
 3 years ago
h
katlin95
 3 years ago
h

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darkb0nebeauty
 3 years ago
Best ResponseYou've already chosen the best response.0what grade ARE YOU IN?

katlin95
 3 years ago
Best ResponseYou've already chosen the best response.112th grade??? why? I just asked for some help, not to be asked what grade im in.. like im stupid or something.

darkb0nebeauty
 3 years ago
Best ResponseYou've already chosen the best response.0I WAS JUST ASKING YOU DONT HAVE TO GET AL L DEFFENSIVE

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1A median is a segment that has as endpoints a vertex of a triangle and the midpoint of the opposite side. An altitude of a triangle is a segment whose endpoint is a vertex of a triangle, is perpendicular to the opposite side, and the other endpoint is on the opposite side. A perpendicular bisector bisects a side of triangle and is perpendiculer to it. It can be a line, and ray or a segment.

Reaper534
 3 years ago
Best ResponseYou've already chosen the best response.0A perpendicular bisector is a segment that is perpendicular to a segment at it’s midpoint. ( 90 degrees ) Perpendicular Bisector Theorem: If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment. A median of a triangle is a segment whose endpoints are a vertex of the triangle and the midpoint of the opposite side. Concurrency of Medians of a Triangle Theorem The medians of a triangle intersect at a point that is twothirds of each segment. The altitudes of a triangle is the perpendicular segment from a vertex to the opposite side or to the line that contains the opposite side. • Concurrency of Altitudes Theorem The lines containing the altitudes of a triangle are concurrent.

katlin95
 3 years ago
Best ResponseYou've already chosen the best response.1yes!:) did u get this from your head @Reaper534

Reaper534
 3 years ago
Best ResponseYou've already chosen the best response.0ofcourse not im not tht smart hahahaha:) im only average some say slightly above
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