A particle is thrown vertically upwards with a speed of 50m/s the ratio of the distance travelled in 2nd second to the last second of its flight is?

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A particle is thrown vertically upwards with a speed of 50m/s the ratio of the distance travelled in 2nd second to the last second of its flight is?

Physics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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T = 2u/g = 100/10 = 10s Dn = u + a/2 (2n-1) D2/D10 = (50 + 5*3)/(50+5*19) = 13/27....Is this Correct
last second = first second
i got my mistake..Since it is projected upwards a = -g...i took it as +g..)

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Other answers:

it shuld be 50-15 / (50 + 5*19)

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