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Yahoo!

  • 3 years ago

A particle is thrown vertically upwards with a speed of 50m/s the ratio of the distance travelled in 2nd second to the last second of its flight is?

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  1. Yahoo!
    • 3 years ago
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    T = 2u/g = 100/10 = 10s Dn = u + a/2 (2n-1) D2/D10 = (50 + 5*3)/(50+5*19) = 13/27....Is this Correct

  2. experimentX
    • 3 years ago
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    last second = first second

  3. Yahoo!
    • 3 years ago
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    i got my mistake..Since it is projected upwards a = -g...i took it as +g..)

  4. Yahoo!
    • 3 years ago
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    it shuld be 50-15 / (50 + 5*19)

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