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anonymous
 4 years ago
R(x) = 2x^5 + 5x^3 + 6x^2 − 6
List all possible rational zeros given by the Rational Zeros Theorem (but don't check to see which actually are zeros). (Enter your answers as a commaseparated list.)
anonymous
 4 years ago
R(x) = 2x^5 + 5x^3 + 6x^2 − 6 List all possible rational zeros given by the Rational Zeros Theorem (but don't check to see which actually are zeros). (Enter your answers as a commaseparated list.)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0came up with + 6 3 2 1 and its wrong =(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The 8 you have are right. However, you're missing two others that aren't integers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0*4 others (with + and )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes hold on let me give you all my numbers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.06,3,2,1,1,2,3,6 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[R(x)=2x^5+5x^3+6x^26\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, that's what I said was correct. But there are 4 nonintegers (fractions) that you're missing.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Am I missing a fraction 1/2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not sure what to do next

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, that's one of the two fractions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay help me with the other fraction please haha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, sure. Can you first tell me how you got these answers? Because I have the answer, but my method may be different.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0+ for both, and that's all the answers, I'm pretty sure. Good job.
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