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sig(n/an2+3)>sig(n/2n2+4n)=sig(1/n+2)=diverge ->sig(n/2n2+3)=diverge

I am sorry but I did not understand fully. Could you give more detail?

Thanks for helping me!

Use limit comparison test with divergent p-series 1/n|dw:1356516645558:dw|

divide by 1/2n instead, it's your question asking for that

Thanks very much - just having a think!

My textbook defines the Comparison Test this way anyhow.

|dw:1356517532318:dw|

in this case, your b series is 1/2n, which is diverge.|dw:1356517694459:dw|

The definition in my textbook is just simple as that. you get it?