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pottersheep
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Intro to rates of change...How do I do this FIRST question? lol :( (see attatched)
 one year ago
 one year ago
pottersheep Group Title
Intro to rates of change...How do I do this FIRST question? lol :( (see attatched)
 one year ago
 one year ago

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pottersheep Group TitleBest ResponseYou've already chosen the best response.0
We only learned power rule
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.1
rate of change is: \[\frac{ \Delta b }{ \Delta t } = \frac{ db }{ dt }\] where b = change in number of bacteria
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
oh we didnt learn that dbthing yet
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
wait thats ust slope?
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ db }{ dt }\] is the derivative, which can be thought of as how much one quantity is changing in response to changes in some other quantity. in this case, it is the change in bacteria amount over time. \[\frac{ \Delta b }{ \Delta t }\] is the same thing, just different notation. \[\Delta = change\] the triangle greek symbol means change. The derivative also represents the slope as you mentioned. It is the tangent line to a particular function, which takes the form: \[\frac{ \Delta y }{ \Delta x } = \frac{ y_2  y_1 }{ x_2  x_1 } = m = slope\]
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.1
I thought this was for a calculus course which is why I mentioned derivatives, but you can ignore the db/dt stuff. You mentioned power rule and I thought of something else. My bad. I didn't mean to confuse you.
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Ohh ok thank you
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Thanks for your help!
 one year ago

abb0t Group TitleBest ResponseYou've already chosen the best response.1
No problem. Good luck.
 one year ago
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