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kirk.freedman

Graph the function 2 ^3√(x+2)+4

  • one year ago
  • one year ago

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  1. kirk.freedman
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    • one year ago
  2. kirk.freedman
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    • one year ago
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  3. kirk.freedman
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    Those are the graphs and the problem.

    • one year ago
  4. kirk.freedman
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    Can you please help @saifoo.khan ?

    • one year ago
  5. saifoo.khan
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    Isn't the attachment 2 and 4 same?

    • one year ago
  6. kirk.freedman
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    Sorry, I screwed that up, lemme re-try

    • one year ago
  7. saifoo.khan
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    Okay. So now which one do you think it should be?

    • one year ago
  8. kirk.freedman
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    I really have no idea :P

    • one year ago
  9. saifoo.khan
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    Do you know how the radical graphs looks like?

    • one year ago
  10. kirk.freedman
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    Hmm, well I guess, kinda, what do you mean?

    • one year ago
  11. saifoo.khan
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    http://www.wmich.edu/cpmp/parentresource/images/c2u4graph6.jpg

    • one year ago
  12. kirk.freedman
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    Oh yeah, I got that.

    • one year ago
  13. saifoo.khan
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    Now try to answer the problem/

    • one year ago
  14. kirk.freedman
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    Lol, sorry, but how? Where do I start?

    • one year ago
  15. saifoo.khan
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    See the "shapes" of the graphs. Match them one by one.

    • one year ago
  16. kirk.freedman
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    I'm so confused :/

    • one year ago
  17. saifoo.khan
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    Do you agree that the problem given to your in a cube-radical?

    • one year ago
  18. kirk.freedman
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    Yes.

    • one year ago
  19. saifoo.khan
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    Okay. No see the shape of cube-radical: http://www.wmich.edu/cpmp/parentresource/images/c2u4graph6.jpg Now match the options one by one.

    • one year ago
  20. kirk.freedman
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    Well it looks like b and c are most similar?

    • one year ago
  21. saifoo.khan
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    Right! Now your problem says 2 ^3√(x+2)+4 Since it's +4, it should be above the value of zero. As in case of opt 2. If it were let's say -1, then it would have been below 0 as in opt 3.

    • one year ago
  22. kirk.freedman
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    So it's b?

    • one year ago
  23. saifoo.khan
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    Yep!

    • one year ago
  24. kirk.freedman
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    Thanks!

    • one year ago
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