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So I know I start by multiplying (x^2+3x-4)(x+4)... I get x^3+7x^2+8x-16 what now?
f • g=x^3+4x^2+3x^2+12x-4x-16=x^3+7x^2+8x-16 the domain means what values can x get, here, x can be any real number. so the domain is all numbers.
How do I know it is all numbers and there isn't like one number that doesn't work? Is there a way to check that?
f/g=(x^2 + 3x – 4)/(x+4) as we know, the denominator can't be equal to 0, so x+4 can't be equal to 0, that means, x can be any number but -4
if there is a square root or a denominator, you must consider that denominator can't be 0 and the expression in the square root is >=0
Wait so what is f/g?
the domain of f/g is any real number but -4
Yeah, that's the domain, but it says find f/g and then it says also find the domain, I thought that that means I need two answers there?
f/g=(x^2 + 3x – 4)/(x+4)
wait, what would be the steps to find that the domain of f/g is all but -4?
is it like x+4>=0 then subtract 4 from both sides so you have x>=-4?
|dw:1356492631732:dw| now what @Hero
Oh yeah, I knew that xD thanks! so it's x-1?
And i'm done now?
Thanks to both of you!