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 one year ago
Prove that if f is measurable, then {x in Ac=f(x)} is measurable for each real number c. Show that the converse is false.
 one year ago
Prove that if f is measurable, then {x in Ac=f(x)} is measurable for each real number c. Show that the converse is false.

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Raja99
 one year ago
Best ResponseYou've already chosen the best response.0can u elaborate the question!

wiah
 one year ago
Best ResponseYou've already chosen the best response.0if f(x) is measurable on a set A, then A(f(x)=c) is measurable for each c.how to prove this?

Raja99
 one year ago
Best ResponseYou've already chosen the best response.0take a example and prove

Raja99
 one year ago
Best ResponseYou've already chosen the best response.0u need have some functions for this

wiah
 one year ago
Best ResponseYou've already chosen the best response.0do u know any link regarding measurable functions?i need to know the proof of all the properties of measurable functions.

Edutopia
 one year ago
Best ResponseYou've already chosen the best response.0http://en.wikipedia.org/wiki/Measurable_function Inverse image "Preimage" redirects here. For the cryptographic attack on hash functions, see preimage attack. Let f be a function from X to Y. The preimage or inverse image of a set B ⊆ Y under f is the subset of X defined by The inverse image of a singleton, denoted by f −1[{y}] or by f −1[y], is also called the fiber over y or the level set of y. The set of all the fibers over the elements of Y is a family of sets indexed by Y. Again, if there is no risk of confusion, we may denote f −1[B] by f −1(B), and think of f −1 as a function from the power set of Y to the power set of X. The notation f −1 should not be confused with that for inverse function. The two coincide only if f is a bijection.

Edutopia
 one year ago
Best ResponseYou've already chosen the best response.0http://www.math.ucdavis.edu/~hunter/measure_theory/measure_notes_ch3.pdf

watchmath
 one year ago
Best ResponseYou've already chosen the best response.0If f is measurable, then for any c, A_c={x  f<c} is measurable and so is the complemant \(A_c^C\). It follows that {x  f(x) =c} =A\ (A_c U A_c^C) is also measurable.
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