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wiah
 2 years ago
Prove that if f is measurable, then {x in Ac=f(x)} is measurable for each real number c. Show that the converse is false.
wiah
 2 years ago
Prove that if f is measurable, then {x in Ac=f(x)} is measurable for each real number c. Show that the converse is false.

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Raja99
 2 years ago
Best ResponseYou've already chosen the best response.0can u elaborate the question!

wiah
 2 years ago
Best ResponseYou've already chosen the best response.0if f(x) is measurable on a set A, then A(f(x)=c) is measurable for each c.how to prove this?

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.0take a example and prove

Raja99
 2 years ago
Best ResponseYou've already chosen the best response.0u need have some functions for this

wiah
 2 years ago
Best ResponseYou've already chosen the best response.0do u know any link regarding measurable functions?i need to know the proof of all the properties of measurable functions.

Edutopia
 2 years ago
Best ResponseYou've already chosen the best response.0http://en.wikipedia.org/wiki/Measurable_function Inverse image "Preimage" redirects here. For the cryptographic attack on hash functions, see preimage attack. Let f be a function from X to Y. The preimage or inverse image of a set B ⊆ Y under f is the subset of X defined by The inverse image of a singleton, denoted by f −1[{y}] or by f −1[y], is also called the fiber over y or the level set of y. The set of all the fibers over the elements of Y is a family of sets indexed by Y. Again, if there is no risk of confusion, we may denote f −1[B] by f −1(B), and think of f −1 as a function from the power set of Y to the power set of X. The notation f −1 should not be confused with that for inverse function. The two coincide only if f is a bijection.

Edutopia
 2 years ago
Best ResponseYou've already chosen the best response.0http://www.math.ucdavis.edu/~hunter/measure_theory/measure_notes_ch3.pdf

watchmath
 2 years ago
Best ResponseYou've already chosen the best response.0If f is measurable, then for any c, A_c={x  f<c} is measurable and so is the complemant \(A_c^C\). It follows that {x  f(x) =c} =A\ (A_c U A_c^C) is also measurable.
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