A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

abb0t
 one year ago
Best ResponseYou've already chosen the best response.2Well, everytime that you move from the left to the right, you jump orbitals. S orbitals can only hold 2 electrons. Those, such as Mg (magnesium) has an electron configuration of: \[1s^2 2s^2 2p^6 3s^2\] When you move to elements such as bromine, carbon, nitrogen, and those below it, they are in the Porbital. The porbitals can hold up to SIX electrons. Since it is in the farthest, 6th position. For instance, Neon [Ne] has an electron configuration: \[1s^2 2s^2 2p^6\] however, carbon has: \[1s^2 2s^2 2p^2\] meaning that it's porbital only has 2 electrons in it's orbital shell. Now, with this information, try and do it for Ca (calcium). I am not sure if your teacher would like, but you can also use:\[[Ne]3s^2\] for magnesium the [Ne] basically just means represents the electron configuration for everything behind neon, which i wrote before. It's shorrthand notation, basically.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.