Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

nicolebears

  • one year ago

Give the electron configuration for the calcium ion

  • This Question is Closed
  1. abb0t
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Well, everytime that you move from the left to the right, you jump orbitals. S orbitals can only hold 2 electrons. Those, such as Mg (magnesium) has an electron configuration of: \[1s^2 2s^2 2p^6 3s^2\] When you move to elements such as bromine, carbon, nitrogen, and those below it, they are in the P-orbital. The p-orbitals can hold up to SIX electrons. Since it is in the farthest, 6th position. For instance, Neon [Ne] has an electron configuration: \[1s^2 2s^2 2p^6\] however, carbon has: \[1s^2 2s^2 2p^2\] meaning that it's p-orbital only has 2 electrons in it's orbital shell. Now, with this information, try and do it for Ca (calcium). I am not sure if your teacher would like, but you can also use:\[[Ne]3s^2\] for magnesium the [Ne] basically just means represents the electron configuration for everything behind neon, which i wrote before. It's shorrt-hand notation, basically.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.