A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
An ice cream parlor sell ice creams with three different flavors: blue
berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams
with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).
 2 years ago
An ice cream parlor sell ice creams with three different flavors: blue berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).

This Question is Closed

Annchelijk
 2 years ago
Best ResponseYou've already chosen the best response.0it means 6C3 + 1 = 20 + 1 = 21 ?

Annchelijk
 2 years ago
Best ResponseYou've already chosen the best response.0Could you explain it clearly ? Thank you

wio
 2 years ago
Best ResponseYou've already chosen the best response.1What I would do is this: 0 vanilla, 12 of chocolate or blueberry 1 vanilla, 11 of chocolate or blueberry 2 vanilla, 10 of chocolate or blueberry ... 6 vanilla, 6 of chocolate or blueberry

wio
 2 years ago
Best ResponseYou've already chosen the best response.1Obviously you add these up.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1So the question is, how to split up 12, 11, 10, ... 6 betwee 2 flavors

wio
 2 years ago
Best ResponseYou've already chosen the best response.1If you start with 12 chocolate and 0 blueberry, you can get any other option by changing a chocolate to a blueberry.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1So you have (12, 0), (11, 1), (10, 2), ... , (0, 12). As you can see, the number of options is 0 to 12... i.e. 13.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1So given 'n' cones, we have 'n+1' options to split then between flavors.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1So the result is: \[ \Large \sum_{n=6}^{12} n+1 = \sum_{n=1}^{12} (n+1)  \sum_{n=1}^{5} (n+1) \]

ashwinjohn3
 2 years ago
Best ResponseYou've already chosen the best response.0Ok...i am gonna explain it....... HERE,THE QUESTIONS SAYS WE MUST HAVE 6 ICECREAM VANILLA FLAVOUR,WHICH IS EQUAL TO ONLY 1 POSSIBLITY....ie=1 And now we can select 6 more ice creams of 3 differnt flavours =6C3 Total possibilties=6C3+1=20+1=21

ashwinjohn3
 2 years ago
Best ResponseYou've already chosen the best response.0@Annchelijk Get it?

mathmate
 2 years ago
Best ResponseYou've already chosen the best response.0The question requires AT MOST 6 vanillas. So Ways to choose AT LEAST 7 vanillas=5C3 Ways to choose 12 ice creams = 12C3 Ways to choose AT MOST 6 vanillas = 12C35C3
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.