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Annchelijk
Group Title
An ice cream parlor sell ice creams with three different flavors: blue
berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams
with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).
 one year ago
 one year ago
Annchelijk Group Title
An ice cream parlor sell ice creams with three different flavors: blue berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).
 one year ago
 one year ago

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Annchelijk Group TitleBest ResponseYou've already chosen the best response.0
it means 6C3 + 1 = 20 + 1 = 21 ?
 one year ago

Annchelijk Group TitleBest ResponseYou've already chosen the best response.0
Could you explain it clearly ? Thank you
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
What I would do is this: 0 vanilla, 12 of chocolate or blueberry 1 vanilla, 11 of chocolate or blueberry 2 vanilla, 10 of chocolate or blueberry ... 6 vanilla, 6 of chocolate or blueberry
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
Obviously you add these up.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
So the question is, how to split up 12, 11, 10, ... 6 betwee 2 flavors
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
If you start with 12 chocolate and 0 blueberry, you can get any other option by changing a chocolate to a blueberry.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
So you have (12, 0), (11, 1), (10, 2), ... , (0, 12). As you can see, the number of options is 0 to 12... i.e. 13.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
So given 'n' cones, we have 'n+1' options to split then between flavors.
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.1
So the result is: \[ \Large \sum_{n=6}^{12} n+1 = \sum_{n=1}^{12} (n+1)  \sum_{n=1}^{5} (n+1) \]
 one year ago

ashwinjohn3 Group TitleBest ResponseYou've already chosen the best response.0
Ok...i am gonna explain it....... HERE,THE QUESTIONS SAYS WE MUST HAVE 6 ICECREAM VANILLA FLAVOUR,WHICH IS EQUAL TO ONLY 1 POSSIBLITY....ie=1 And now we can select 6 more ice creams of 3 differnt flavours =6C3 Total possibilties=6C3+1=20+1=21
 one year ago

ashwinjohn3 Group TitleBest ResponseYou've already chosen the best response.0
@Annchelijk Get it?
 one year ago

mathmate Group TitleBest ResponseYou've already chosen the best response.0
The question requires AT MOST 6 vanillas. So Ways to choose AT LEAST 7 vanillas=5C3 Ways to choose 12 ice creams = 12C3 Ways to choose AT MOST 6 vanillas = 12C35C3
 one year ago
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