Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
An ice cream parlor sell ice creams with three different flavors: blue
berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams
with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).
 one year ago
 one year ago
An ice cream parlor sell ice creams with three different flavors: blue berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).
 one year ago
 one year ago

This Question is Closed

AnnchelijkBest ResponseYou've already chosen the best response.0
it means 6C3 + 1 = 20 + 1 = 21 ?
 one year ago

AnnchelijkBest ResponseYou've already chosen the best response.0
Could you explain it clearly ? Thank you
 one year ago

wioBest ResponseYou've already chosen the best response.1
What I would do is this: 0 vanilla, 12 of chocolate or blueberry 1 vanilla, 11 of chocolate or blueberry 2 vanilla, 10 of chocolate or blueberry ... 6 vanilla, 6 of chocolate or blueberry
 one year ago

wioBest ResponseYou've already chosen the best response.1
Obviously you add these up.
 one year ago

wioBest ResponseYou've already chosen the best response.1
So the question is, how to split up 12, 11, 10, ... 6 betwee 2 flavors
 one year ago

wioBest ResponseYou've already chosen the best response.1
If you start with 12 chocolate and 0 blueberry, you can get any other option by changing a chocolate to a blueberry.
 one year ago

wioBest ResponseYou've already chosen the best response.1
So you have (12, 0), (11, 1), (10, 2), ... , (0, 12). As you can see, the number of options is 0 to 12... i.e. 13.
 one year ago

wioBest ResponseYou've already chosen the best response.1
So given 'n' cones, we have 'n+1' options to split then between flavors.
 one year ago

wioBest ResponseYou've already chosen the best response.1
So the result is: \[ \Large \sum_{n=6}^{12} n+1 = \sum_{n=1}^{12} (n+1)  \sum_{n=1}^{5} (n+1) \]
 one year ago

ashwinjohn3Best ResponseYou've already chosen the best response.0
Ok...i am gonna explain it....... HERE,THE QUESTIONS SAYS WE MUST HAVE 6 ICECREAM VANILLA FLAVOUR,WHICH IS EQUAL TO ONLY 1 POSSIBLITY....ie=1 And now we can select 6 more ice creams of 3 differnt flavours =6C3 Total possibilties=6C3+1=20+1=21
 one year ago

ashwinjohn3Best ResponseYou've already chosen the best response.0
@Annchelijk Get it?
 one year ago

mathmateBest ResponseYou've already chosen the best response.0
The question requires AT MOST 6 vanillas. So Ways to choose AT LEAST 7 vanillas=5C3 Ways to choose 12 ice creams = 12C3 Ways to choose AT MOST 6 vanillas = 12C35C3
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.