Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Annchelijk Group Title

An ice cream parlor sell ice creams with three different flavors: blue- berry, chocolates, and vanilla. How many ways are there to choose a dozen ice creams with at most six vanilla ice creams? (Note: one dozen consists of twelve ice creams).

  • one year ago
  • one year ago

  • This Question is Closed
  1. ashwinjohn3 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    6C3+1

    • one year ago
  2. Annchelijk Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    it means 6C3 + 1 = 20 + 1 = 21 ?

    • one year ago
  3. Annchelijk Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Could you explain it clearly ? Thank you

    • one year ago
  4. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    What I would do is this: 0 vanilla, 12 of chocolate or blueberry 1 vanilla, 11 of chocolate or blueberry 2 vanilla, 10 of chocolate or blueberry ... 6 vanilla, 6 of chocolate or blueberry

    • one year ago
  5. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Obviously you add these up.

    • one year ago
  6. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So the question is, how to split up 12, 11, 10, ... 6 betwee 2 flavors

    • one year ago
  7. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    If you start with 12 chocolate and 0 blueberry, you can get any other option by changing a chocolate to a blueberry.

    • one year ago
  8. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So you have (12, 0), (11, 1), (10, 2), ... , (0, 12). As you can see, the number of options is 0 to 12... i.e. 13.

    • one year ago
  9. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So given 'n' cones, we have 'n+1' options to split then between flavors.

    • one year ago
  10. wio Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So the result is: \[ \Large \sum_{n=6}^{12} n+1 = \sum_{n=1}^{12} (n+1) - \sum_{n=1}^{5} (n+1) \]

    • one year ago
  11. ashwinjohn3 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok...i am gonna explain it....... HERE,THE QUESTIONS SAYS WE MUST HAVE 6 ICECREAM VANILLA FLAVOUR,WHICH IS EQUAL TO ONLY 1 POSSIBLITY....ie=1 And now we can select 6 more ice creams of 3 differnt flavours =6C3 Total possibilties=6C3+1=20+1=21

    • one year ago
  12. ashwinjohn3 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @Annchelijk Get it?

    • one year ago
  13. mathmate Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    The question requires AT MOST 6 vanillas. So Ways to choose AT LEAST 7 vanillas=5C3 Ways to choose 12 ice creams = 12C3 Ways to choose AT MOST 6 vanillas = 12C3-5C3

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.