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Krishnadas
Group Title
please help..whats wrong in this?
let a=x
a+x=2x
a+x2a=2x2a
xa=2(xa)
1=2...
 one year ago
 one year ago
Krishnadas Group Title
please help..whats wrong in this? let a=x a+x=2x a+x2a=2x2a xa=2(xa) 1=2...
 one year ago
 one year ago

This Question is Closed

hartnn Group TitleBest ResponseYou've already chosen the best response.2
since x=a xa =0 one cannot divide by 0
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
@hartnn i think so
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
u mean u 'thought' so ?
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
nah!I said your answer makes sense
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
ohh...yes...any more doubts ?
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
just a minute...i have one
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
@hartnn is 0/0=infinity?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
no, 0/0 is not defined.
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
so... (100100)/(100100) is not defined 10^210^2/(10(1010)) is not defined (10+10)(1010)/(10(1010)) is not defined ...cancelling (1010) 10+10/10 is not defined 20/10=2 is not defined????
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
again, cannot cancel, 1010
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
by cancelling 1010=0 you are removing the part that was not defined so the part which was defined, remains, which is 2=2
 one year ago

Krishnadas Group TitleBest ResponseYou've already chosen the best response.0
oh my god!!That thing was my doubt for 2 years...Thanks buddy...@hartnn
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
hmmm... welcome ^_^
 one year ago
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