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 one year ago
The magnitude of the electric field vector on the ground is 100 N/C and it's direction towards the ground and perpendicular to it . The magnitude decreases as we go further from the ground till it reaches 20N/C at height 1400m.
Calculate the average volume charge density (ρ) of the air layer between the ground and this height.
 one year ago
The magnitude of the electric field vector on the ground is 100 N/C and it's direction towards the ground and perpendicular to it . The magnitude decreases as we go further from the ground till it reaches 20N/C at height 1400m. Calculate the average volume charge density (ρ) of the air layer between the ground and this height.

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VincentLyon.Fr
 one year ago
Best ResponseYou've already chosen the best response.1Do you know MaxwellGauß equation: \(\vec\nabla.\vec E = \rho/\epsilon_o\)

y2o2
 one year ago
Best ResponseYou've already chosen the best response.0Actually No , I still haven't studied the all the Maxwell equations. I studied Gauss law , but I didn't study the divergence form of it. I don't know if it can be solved by Gauss law. \[{\int\limits_{}^{} E.dA = } {Q \over \epsilon_o}\]

VincentLyon.Fr
 one year ago
Best ResponseYou've already chosen the best response.1Ok, now you have to choose a Gaussian surface that goes from the altitude O to 1400 m. Work out flux of E, then you will get Q. Divide by volume and you will get \(\rho\).

y2o2
 one year ago
Best ResponseYou've already chosen the best response.0I thought of this , but I couldn't do it. because I don't know the right G.surface to choose , and also I wasn't given any area to find a volume

VincentLyon.Fr
 one year ago
Best ResponseYou've already chosen the best response.1Use any cylinder of base A and height h = 1400 metres. Volume inside cylinder will be: V = A.h
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