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y2o2
 3 years ago
The magnitude of the electric field vector on the ground is 100 N/C and it's direction towards the ground and perpendicular to it . The magnitude decreases as we go further from the ground till it reaches 20N/C at height 1400m.
Calculate the average volume charge density (ρ) of the air layer between the ground and this height.
y2o2
 3 years ago
The magnitude of the electric field vector on the ground is 100 N/C and it's direction towards the ground and perpendicular to it . The magnitude decreases as we go further from the ground till it reaches 20N/C at height 1400m. Calculate the average volume charge density (ρ) of the air layer between the ground and this height.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know MaxwellGauß equation: \(\vec\nabla.\vec E = \rho/\epsilon_o\)

y2o2
 3 years ago
Best ResponseYou've already chosen the best response.0Actually No , I still haven't studied the all the Maxwell equations. I studied Gauss law , but I didn't study the divergence form of it. I don't know if it can be solved by Gauss law. \[{\int\limits_{}^{} E.dA = } {Q \over \epsilon_o}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, now you have to choose a Gaussian surface that goes from the altitude O to 1400 m. Work out flux of E, then you will get Q. Divide by volume and you will get \(\rho\).

y2o2
 3 years ago
Best ResponseYou've already chosen the best response.0I thought of this , but I couldn't do it. because I don't know the right G.surface to choose , and also I wasn't given any area to find a volume

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Use any cylinder of base A and height h = 1400 metres. Volume inside cylinder will be: V = A.h
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