anonymous
  • anonymous
Guys I'm sad because I haven't done my math in like 6 months because I hate radicals. :( Help me pwease? It's probably super easy but my lesson doesn't explain much and my teacher refuses to help. Change this radical to an algebraic expression with fractional exponents. 3√a
Mathematics
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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UnkleRhaukus
  • UnkleRhaukus
\[\sqrt x=x^{1/2}\]
anonymous
  • anonymous
a^(1/3). Basically the rule here is fairly simple. Say you have 2√x^3 (square root of x to the power of 3. What you do is take the "to the power of" portion and divide it by what kind of root it is (ie. squared is 2, cubed is 3...etc). So what you get is x^3/2
anonymous
  • anonymous
What about the 3? I'm really sorry I just don't know and it's really stressing me out :( I'm lame.

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UnkleRhaukus
  • UnkleRhaukus
\[\sqrt[n]x=x^{1/n}\]
anonymous
  • anonymous
Ohhhhhh Thanks @Evgeny I'm in Alg II and I have an A but I almost failed Alg I and my teacher was like "Well you should've learned that in Alg I...so figure it out" :/
UnkleRhaukus
  • UnkleRhaukus
\[\sqrt[n]{x^m}=(\sqrt[n]x)^m=x^\frac mn\]
anonymous
  • anonymous
Thank you @UnkleRhaukus I will do my best to remember all of this. I will probably still ask for more help haha
UnkleRhaukus
  • UnkleRhaukus
thats why we are here. \[\color{teal}{\ddot\smile}\]
anonymous
  • anonymous
Would √b just be b^2? Or something...
hba
  • hba
@yololol No you are wrong \[\sqrt{b}=(b)^{1/2}\]
anonymous
  • anonymous
It doesn't give me a fraction as an option, idt...hold on
anonymous
  • anonymous
Okay, it doesn't give it as an option to be an exponent so maybe they'll just assume it's an exponent and I'll hope for the best. Thank you! Sorry about my dumb questions. OMG it's Joker!! :D xD
precal
  • precal
|dw:1356577815740:dw|not sure which one you meant, so I wrot both versions out for you

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