A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

Kainui
 one year ago
Best ResponseYou've already chosen the best response.0What do you mean? They could both have the same strength, but not the same vectors.

neha123
 one year ago
Best ResponseYou've already chosen the best response.0find electric field caused by a sphere of radius R with uniform surface charge density sigma at a point along axis of disk at a distance x from its centre should i follw same method as for a disk?.

ghazi
 one year ago
Best ResponseYou've already chosen the best response.1electric field at a distance R by sphere of uniform charge density is if R> radius of sphere \[E=\frac{ Q }{ 4 \pi \epsilon R^2 }\] and for R < radius of sphere (A) is \[E=\frac{ Q R }{ 4 \pi \epsilon A^3 }\] now if we talk about disc then, lets say at a distance X from the center of disc along the axis of rotation \[E=2 \pi \sigma k(1 \frac{ X }{ \sqrt{X^2+R^2} } )\] for X>0, R is radius of disc and for X<R electric field is \[E \approx 2 \pi \sigma k\]

ghazi
 one year ago
Best ResponseYou've already chosen the best response.1now, i hope you can better judge and analyse if its same and at what distance or not :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.