anonymous
  • anonymous
PLEASE HELP!!!! Solve the system, using substitution. One point for correct steps, one point for correct ordered pair, (a,b). a + b = 4 and 2a + 3b = 11 i tried to solve for a but ended up with 1/-5 i dont think thats right....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1356562594798:dw|
anonymous
  • anonymous
a+b=4 2a+3b=11 a=4-b 2(4-b)+3b=11 (substituing a as found) a=4-b 8+b=11 a=4-b b=3 so, a=1 and b=3
anonymous
  • anonymous
a=4-b 2(4-b)+3b=11 i get that but how did ypu go from that to a=4-b 8+b=11

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More answers

anonymous
  • anonymous
you need first to isolate a or b in one of the equations, and use this on the other. I have skipped one or two steps, but if you do correctly, the answer (a,b)=(1,3) will be found
anonymous
  • anonymous
2(4-b) = 8-2b, write it and keep solving
anonymous
  • anonymous
This problem is about solving what is called 'linear system'. You have some equations with letters and need to find what are their values. Further you will see that not all of this kind of systems can be solved (when there are more letters than equations) - but you can just ignore it by now tell me when you're done, it just a matter of practice to solve it better an faster
anonymous
  • anonymous
ok question: in 2(4-b)+3b=11 would it equal 8-b+3b=11 or 8-2b+3b=11?
anonymous
  • anonymous
8-2b+3b=11
anonymous
  • anonymous
because the 2 multipies both 4 and -b in 2(4-b)
anonymous
  • anonymous
this is what i got 8-b+3b=11 8+2b=11 2b=11-8 2b=3 2b/2=3/2
anonymous
  • anonymous
re-do it haha it is 8-2b+3b=11 but what you've done is right if it was 8-b+3b=11
anonymous
  • anonymous
|dw:1356564451980:dw|
anonymous
  • anonymous
kind of what taylor said... You need to do all by yourself, and just ask for some tips. Because it is when you think alone that you really understand. try and try and try. It's hard, but sometime there will be just the right answer
anonymous
  • anonymous
Yup. U cant just go on the internet and find answers for everything and anything. Theres a reason its in ur text books, and theres a reason teachers teach it to u. If u paid attention, u wouldnt be askin questions on OpenStudy ;-)
anonymous
  • anonymous
im not trying to gte an easy answer i honestly dont understand this also i didnt respond bcs my inter net went out
anonymous
  • anonymous
I was just complementing. Just to say, first step, you can ask a lot about your doubt, but with time, you will do it without any help. haha
anonymous
  • anonymous
im really confused about what to do after i get -2b=3 can you please continue to help me?
anonymous
  • anonymous
i'm here. Let's see..
anonymous
  • anonymous
where is -2b=3 ?
anonymous
  • anonymous
8-2b=11 -2b=11-8 -2b=3
anonymous
  • anonymous
you have a+b=4 2a+3b=11 then, you use ANY of these equations to isolate a letter in the case, I've used the first and came up with a=4-b (so, from now on, that's what a is) you could also do it in the second, but that's too much work
anonymous
  • anonymous
I isolated a, but it could be also b. both correct
anonymous
  • anonymous
thisd is what ive done a + b = 4 and 2a + 3b = 11 2(4-b)+3b=11 8-b+3b=11 8-2b=11 -2b=11-8 -2b=3
anonymous
  • anonymous
what next?
anonymous
  • anonymous
2(4-b)+3b=11 8-b+3b=11 This is not right, because when you multiply a number times something in parenthesis, everything inside is multiplied so 2(4-b)+3b=11 what comes next?
anonymous
  • anonymous
8-2b+3b=11?
anonymous
  • anonymous
yes!
anonymous
  • anonymous
and i guess, if you go back to my first post, it will make more sense now
anonymous
  • anonymous
8-1b=11 -1b=11-8 -1b=3 -1b/-1=3/-1 b=-3 is that right
anonymous
  • anonymous
nonononoooo you've got 8-2b+3b=11 which is equal to 8+b=11 not 8-b=11
anonymous
  • anonymous
8+b=11 b=3 ??
anonymous
  • anonymous
YES! hahahaha
anonymous
  • anonymous
XD
anonymous
  • anonymous
(1,3) ?
anonymous
  • anonymous
That's it :)
anonymous
  • anonymous
thank you for taking the time to help me!
anonymous
  • anonymous
i've found the khan academy page on algebra. https://www.khanacademy.org/math/algebra This may help you
anonymous
  • anonymous
and you're welcome

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