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|dw:1356562594798:dw|

a+b=4
2a+3b=11
a=4-b
2(4-b)+3b=11 (substituing a as found)
a=4-b
8+b=11
a=4-b
b=3
so, a=1 and b=3

a=4-b
2(4-b)+3b=11
i get that but how did ypu go from that to a=4-b
8+b=11

2(4-b) = 8-2b, write it and keep solving

ok question: in 2(4-b)+3b=11 would it equal 8-b+3b=11 or 8-2b+3b=11?

8-2b+3b=11

because the 2 multipies both 4 and -b in 2(4-b)

this is what i got 8-b+3b=11
8+2b=11
2b=11-8
2b=3
2b/2=3/2

re-do it haha
it is 8-2b+3b=11
but what you've done is right if it was 8-b+3b=11

|dw:1356564451980:dw|

im really confused about what to do after i get -2b=3 can you please continue to help me?

i'm here. Let's see..

where is -2b=3 ?

8-2b=11
-2b=11-8
-2b=3

I isolated a, but it could be also b. both correct

thisd is what ive done a + b = 4 and 2a + 3b = 11
2(4-b)+3b=11
8-b+3b=11
8-2b=11
-2b=11-8
-2b=3

what next?

8-2b+3b=11?

yes!

and i guess, if you go back to my first post, it will make more sense now

8-1b=11
-1b=11-8
-1b=3
-1b/-1=3/-1
b=-3
is that right

nonononoooo
you've got
8-2b+3b=11
which is equal to
8+b=11
not 8-b=11

8+b=11
b=3
??

YES! hahahaha

XD

(1,3)
?

That's it :)

thank you for taking the time to help me!

and you're welcome