and again

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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1 Attachment
Why don't u learn how to do them instead of asking for answers???
  • phi
This is the same problem as before. Just different numbers.

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Well if you knew me good enough you would now that I don't learn real easy. It isn't that I am choosing not to learn I just don't get how to do it.
|dw:1356563774476:dw|
Multiply both sides by 7.
-35 and -7?
|dw:1356563975056:dw|
Am I right?
Add 5 to both sides.
-30 and -2?
|dw:1356564176650:dw|
  • phi
no, when you multiply 7 times (z-5)/7 \[ \frac{7}{1}\cdot \frac{(z-5)}{7} \] you get \[\frac{7(z-5)}{7} \] or \[ \frac{7}{7}\cdot \frac{(z-5)}{1} \] 7/7 is 1 and (z-5)/1 is (z-5) multiplying by the 7 makes the denominator "go away"
OK????
  • phi
see skull's first post
what about it?
  • phi
you do not get -35 and -7? you get z-5= -7
ok. but never mind
The answer is {-2} because -2 is the only number that will make z = -2 a true statement.
-2 = -2
ok but the only reason I am asking these questions is because I dont get how to do them @Harkirat
@chevygirl Well ask your teacher to explain,in detail, how to solve such sums....u cannot go through life asking others to solve them for you......being able to do themselves will boost your confidence...
well if my teachers were here i would ask them but they arent here so I cant AND i got put in a different class because i got behind because i am not good at math
|dw:1356564567196:dw|
ok. i will try to REMEMBER this
Would you like me to explain how I solved the original equation?
um no thanks cause i have to do another test
Is it a math test?
yeah
If I explain this one you can use the method on most of your other questions.
yeah but i dont know if it is these type of questions or not
There are a lot of these types of questions in math.
What grade level?
7
Do you know what an inverse operation is?
yeah
inverse operations: Operations that "undo" each other for example multiplication and division.
If the side containing the variable involves a certain order of operations, apply the inverse operations in the opposite order.

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