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anonymous
 4 years ago
and again
anonymous
 4 years ago
and again

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why don't u learn how to do them instead of asking for answers???

phi
 4 years ago
Best ResponseYou've already chosen the best response.0This is the same problem as before. Just different numbers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well if you knew me good enough you would now that I don't learn real easy. It isn't that I am choosing not to learn I just don't get how to do it.

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1356563774476:dw

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1Multiply both sides by 7.

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1356563975056:dw

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1Add 5 to both sides.

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1356564176650:dw

phi
 4 years ago
Best ResponseYou've already chosen the best response.0no, when you multiply 7 times (z5)/7 \[ \frac{7}{1}\cdot \frac{(z5)}{7} \] you get \[\frac{7(z5)}{7} \] or \[ \frac{7}{7}\cdot \frac{(z5)}{1} \] 7/7 is 1 and (z5)/1 is (z5) multiplying by the 7 makes the denominator "go away"

phi
 4 years ago
Best ResponseYou've already chosen the best response.0you do not get 35 and 7? you get z5= 7

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1The answer is {2} because 2 is the only number that will make z = 2 a true statement.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok but the only reason I am asking these questions is because I dont get how to do them @Harkirat

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@chevygirl Well ask your teacher to explain,in detail, how to solve such sums....u cannot go through life asking others to solve them for you......being able to do themselves will boost your confidence...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well if my teachers were here i would ask them but they arent here so I cant AND i got put in a different class because i got behind because i am not good at math

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1356564567196:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. i will try to REMEMBER this

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1Would you like me to explain how I solved the original equation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0um no thanks cause i have to do another test

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1If I explain this one you can use the method on most of your other questions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but i dont know if it is these type of questions or not

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1There are a lot of these types of questions in math.

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1Do you know what an inverse operation is?

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1inverse operations: Operations that "undo" each other for example multiplication and division.

skullpatrol
 4 years ago
Best ResponseYou've already chosen the best response.1If the side containing the variable involves a certain order of operations, apply the inverse operations in the opposite order.
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