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HarkiratBest ResponseYou've already chosen the best response.0
Why don't u learn how to do them instead of asking for answers???
 one year ago

phiBest ResponseYou've already chosen the best response.0
This is the same problem as before. Just different numbers.
 one year ago

chevygirlBest ResponseYou've already chosen the best response.0
Well if you knew me good enough you would now that I don't learn real easy. It isn't that I am choosing not to learn I just don't get how to do it.
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
dw:1356563774476:dw
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
Multiply both sides by 7.
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
dw:1356563975056:dw
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
Add 5 to both sides.
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
dw:1356564176650:dw
 one year ago

phiBest ResponseYou've already chosen the best response.0
no, when you multiply 7 times (z5)/7 \[ \frac{7}{1}\cdot \frac{(z5)}{7} \] you get \[\frac{7(z5)}{7} \] or \[ \frac{7}{7}\cdot \frac{(z5)}{1} \] 7/7 is 1 and (z5)/1 is (z5) multiplying by the 7 makes the denominator "go away"
 one year ago

phiBest ResponseYou've already chosen the best response.0
you do not get 35 and 7? you get z5= 7
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
The answer is {2} because 2 is the only number that will make z = 2 a true statement.
 one year ago

chevygirlBest ResponseYou've already chosen the best response.0
ok but the only reason I am asking these questions is because I dont get how to do them @Harkirat
 one year ago

HarkiratBest ResponseYou've already chosen the best response.0
@chevygirl Well ask your teacher to explain,in detail, how to solve such sums....u cannot go through life asking others to solve them for you......being able to do themselves will boost your confidence...
 one year ago

chevygirlBest ResponseYou've already chosen the best response.0
well if my teachers were here i would ask them but they arent here so I cant AND i got put in a different class because i got behind because i am not good at math
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
dw:1356564567196:dw
 one year ago

chevygirlBest ResponseYou've already chosen the best response.0
ok. i will try to REMEMBER this
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
Would you like me to explain how I solved the original equation?
 one year ago

chevygirlBest ResponseYou've already chosen the best response.0
um no thanks cause i have to do another test
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
Is it a math test?
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
If I explain this one you can use the method on most of your other questions.
 one year ago

chevygirlBest ResponseYou've already chosen the best response.0
yeah but i dont know if it is these type of questions or not
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
There are a lot of these types of questions in math.
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
Do you know what an inverse operation is?
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
inverse operations: Operations that "undo" each other for example multiplication and division.
 one year ago

skullpatrolBest ResponseYou've already chosen the best response.1
If the side containing the variable involves a certain order of operations, apply the inverse operations in the opposite order.
 one year ago
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