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chevygirl

  • one year ago

and again

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  1. chevygirl
    • one year ago
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  2. Harkirat
    • one year ago
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    Why don't u learn how to do them instead of asking for answers???

  3. phi
    • one year ago
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    This is the same problem as before. Just different numbers.

  4. chevygirl
    • one year ago
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    Well if you knew me good enough you would now that I don't learn real easy. It isn't that I am choosing not to learn I just don't get how to do it.

  5. skullpatrol
    • one year ago
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    |dw:1356563774476:dw|

  6. skullpatrol
    • one year ago
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    Multiply both sides by 7.

  7. chevygirl
    • one year ago
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    -35 and -7?

  8. skullpatrol
    • one year ago
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    |dw:1356563975056:dw|

  9. chevygirl
    • one year ago
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    Am I right?

  10. skullpatrol
    • one year ago
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    Add 5 to both sides.

  11. chevygirl
    • one year ago
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    -30 and -2?

  12. skullpatrol
    • one year ago
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    |dw:1356564176650:dw|

  13. phi
    • one year ago
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    no, when you multiply 7 times (z-5)/7 \[ \frac{7}{1}\cdot \frac{(z-5)}{7} \] you get \[\frac{7(z-5)}{7} \] or \[ \frac{7}{7}\cdot \frac{(z-5)}{1} \] 7/7 is 1 and (z-5)/1 is (z-5) multiplying by the 7 makes the denominator "go away"

  14. chevygirl
    • one year ago
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    OK????

  15. phi
    • one year ago
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    see skull's first post

  16. chevygirl
    • one year ago
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    what about it?

  17. phi
    • one year ago
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    you do not get -35 and -7? you get z-5= -7

  18. chevygirl
    • one year ago
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    ok. but never mind

  19. skullpatrol
    • one year ago
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    The answer is {-2} because -2 is the only number that will make z = -2 a true statement.

  20. skullpatrol
    • one year ago
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    -2 = -2

  21. chevygirl
    • one year ago
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    ok but the only reason I am asking these questions is because I dont get how to do them @Harkirat

  22. Harkirat
    • one year ago
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    @chevygirl Well ask your teacher to explain,in detail, how to solve such sums....u cannot go through life asking others to solve them for you......being able to do themselves will boost your confidence...

  23. chevygirl
    • one year ago
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    well if my teachers were here i would ask them but they arent here so I cant AND i got put in a different class because i got behind because i am not good at math

  24. skullpatrol
    • one year ago
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    |dw:1356564567196:dw|

  25. chevygirl
    • one year ago
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    ok. i will try to REMEMBER this

  26. skullpatrol
    • one year ago
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    Would you like me to explain how I solved the original equation?

  27. chevygirl
    • one year ago
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    um no thanks cause i have to do another test

  28. skullpatrol
    • one year ago
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    Is it a math test?

  29. chevygirl
    • one year ago
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    yeah

  30. skullpatrol
    • one year ago
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    If I explain this one you can use the method on most of your other questions.

  31. chevygirl
    • one year ago
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    yeah but i dont know if it is these type of questions or not

  32. skullpatrol
    • one year ago
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    There are a lot of these types of questions in math.

  33. skullpatrol
    • one year ago
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    What grade level?

  34. chevygirl
    • one year ago
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    7

  35. skullpatrol
    • one year ago
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    Do you know what an inverse operation is?

  36. chevygirl
    • one year ago
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    yeah

  37. skullpatrol
    • one year ago
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    inverse operations: Operations that "undo" each other for example multiplication and division.

  38. skullpatrol
    • one year ago
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    If the side containing the variable involves a certain order of operations, apply the inverse operations in the opposite order.

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