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chevygirl

and again

  • one year ago
  • one year ago

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  1. chevygirl
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    • one year ago
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  2. Harkirat
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    Why don't u learn how to do them instead of asking for answers???

    • one year ago
  3. phi
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    This is the same problem as before. Just different numbers.

    • one year ago
  4. chevygirl
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    Well if you knew me good enough you would now that I don't learn real easy. It isn't that I am choosing not to learn I just don't get how to do it.

    • one year ago
  5. skullpatrol
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    |dw:1356563774476:dw|

    • one year ago
  6. skullpatrol
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    Multiply both sides by 7.

    • one year ago
  7. chevygirl
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    -35 and -7?

    • one year ago
  8. skullpatrol
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    |dw:1356563975056:dw|

    • one year ago
  9. chevygirl
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    Am I right?

    • one year ago
  10. skullpatrol
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    Add 5 to both sides.

    • one year ago
  11. chevygirl
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    -30 and -2?

    • one year ago
  12. skullpatrol
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    |dw:1356564176650:dw|

    • one year ago
  13. phi
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    no, when you multiply 7 times (z-5)/7 \[ \frac{7}{1}\cdot \frac{(z-5)}{7} \] you get \[\frac{7(z-5)}{7} \] or \[ \frac{7}{7}\cdot \frac{(z-5)}{1} \] 7/7 is 1 and (z-5)/1 is (z-5) multiplying by the 7 makes the denominator "go away"

    • one year ago
  14. chevygirl
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    OK????

    • one year ago
  15. phi
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    see skull's first post

    • one year ago
  16. chevygirl
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    what about it?

    • one year ago
  17. phi
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    you do not get -35 and -7? you get z-5= -7

    • one year ago
  18. chevygirl
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    ok. but never mind

    • one year ago
  19. skullpatrol
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    The answer is {-2} because -2 is the only number that will make z = -2 a true statement.

    • one year ago
  20. skullpatrol
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    -2 = -2

    • one year ago
  21. chevygirl
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    ok but the only reason I am asking these questions is because I dont get how to do them @Harkirat

    • one year ago
  22. Harkirat
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    @chevygirl Well ask your teacher to explain,in detail, how to solve such sums....u cannot go through life asking others to solve them for you......being able to do themselves will boost your confidence...

    • one year ago
  23. chevygirl
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    well if my teachers were here i would ask them but they arent here so I cant AND i got put in a different class because i got behind because i am not good at math

    • one year ago
  24. skullpatrol
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    |dw:1356564567196:dw|

    • one year ago
  25. chevygirl
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    ok. i will try to REMEMBER this

    • one year ago
  26. skullpatrol
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    Would you like me to explain how I solved the original equation?

    • one year ago
  27. chevygirl
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    um no thanks cause i have to do another test

    • one year ago
  28. skullpatrol
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    Is it a math test?

    • one year ago
  29. chevygirl
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    yeah

    • one year ago
  30. skullpatrol
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    If I explain this one you can use the method on most of your other questions.

    • one year ago
  31. chevygirl
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    yeah but i dont know if it is these type of questions or not

    • one year ago
  32. skullpatrol
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    There are a lot of these types of questions in math.

    • one year ago
  33. skullpatrol
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    What grade level?

    • one year ago
  34. chevygirl
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    7

    • one year ago
  35. skullpatrol
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    Do you know what an inverse operation is?

    • one year ago
  36. chevygirl
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    yeah

    • one year ago
  37. skullpatrol
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    inverse operations: Operations that "undo" each other for example multiplication and division.

    • one year ago
  38. skullpatrol
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    If the side containing the variable involves a certain order of operations, apply the inverse operations in the opposite order.

    • one year ago
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