and again

- anonymous

and again

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

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- anonymous

##### 1 Attachment

- anonymous

Why don't u learn how to do them instead of asking for answers???

- phi

This is the same problem as before. Just different numbers.

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## More answers

- anonymous

Well if you knew me good enough you would now that I don't learn real easy. It isn't that I am choosing not to learn I just don't get how to do it.

- skullpatrol

|dw:1356563774476:dw|

- skullpatrol

Multiply both sides by 7.

- anonymous

-35 and -7?

- skullpatrol

|dw:1356563975056:dw|

- anonymous

Am I right?

- skullpatrol

Add 5 to both sides.

- anonymous

-30 and -2?

- skullpatrol

|dw:1356564176650:dw|

- phi

no, when you multiply 7 times (z-5)/7
\[ \frac{7}{1}\cdot \frac{(z-5)}{7} \]
you get
\[\frac{7(z-5)}{7} \] or
\[ \frac{7}{7}\cdot \frac{(z-5)}{1} \]
7/7 is 1
and (z-5)/1 is (z-5)
multiplying by the 7 makes the denominator "go away"

- anonymous

OK????

- phi

see skull's first post

- anonymous

what about it?

- phi

you do not get
-35 and -7?
you get
z-5= -7

- anonymous

ok. but never mind

- skullpatrol

The answer is {-2} because -2 is the only number that will make z = -2 a true statement.

- skullpatrol

-2 = -2

- anonymous

ok but the only reason I am asking these questions is because I dont get how to do them @Harkirat

- anonymous

@chevygirl
Well ask your teacher to explain,in detail, how to solve such sums....u cannot go through life asking others to solve them for you......being able to do themselves will boost your confidence...

- anonymous

well if my teachers were here i would ask them but they arent here so I cant AND i got put in a different class because i got behind because i am not good at math

- skullpatrol

|dw:1356564567196:dw|

- anonymous

ok. i will try to REMEMBER this

- skullpatrol

Would you like me to explain how I solved the original equation?

- anonymous

um no thanks cause i have to do another test

- skullpatrol

Is it a math test?

- anonymous

yeah

- skullpatrol

If I explain this one you can use the method on most of your other questions.

- anonymous

yeah but i dont know if it is these type of questions or not

- skullpatrol

There are a lot of these types of questions in math.

- skullpatrol

What grade level?

- anonymous

7

- skullpatrol

Do you know what an inverse operation is?

- anonymous

yeah

- skullpatrol

inverse operations: Operations that "undo" each other for example multiplication and division.

- skullpatrol

If the side containing the variable involves a certain order of operations, apply the inverse operations in the opposite order.

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