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pottersheep

  • 3 years ago

I'm confused about rates of change? Why don't I put this into the limit formula? (Grade 12 Adv Functions) Question: As you get father from the earth's surface, gravity has less effect on you. For this reason, you actually weigh less at higher altitudes. A person who weighs 55kg can use this function to find out their weight: [6400(55)]/(h+6400), at a specific height (h) above sea evel. Find the instantaneous rate of change at 12000 ft above sea level. How my teacher told me to do it: [w(12000.001-w(1199.999)]/0.002 = 0.00609 Whatever happened to using LIMITS ?

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  1. jefftheloveableguy
    • 3 years ago
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    This Newton's law of universal gravitation i think. Well i guess when taking a limit all you need to do is directly plug in the value into h. This would be the limit as h approached 12000 feet?

  2. pottersheep
    • 3 years ago
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    Isnt this like a "cheat" way to do limits? What happened to properly using the formula?

  3. wio
    • 3 years ago
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    He's not giving you the instantaneous rate of change then, hes giving you the average rate of change over a small interval. If you wanna do a limit you can.

  4. jefftheloveableguy
    • 3 years ago
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    Right i guess so. What he is doing is dw/d(something i dont know) so dw would be a differential and i dont know what the 0.002 is. By the way are you in 12th grade AP physics?

  5. jefftheloveableguy
    • 3 years ago
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    the d of something i dont know would not be the 55 kg because that stays constant

  6. pottersheep
    • 3 years ago
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    Thanks guys

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