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pottersheep
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I'm confused about rates of change? Why don't I put this into the limit formula? (Grade 12 Adv Functions)
Question: As you get father from the earth's surface, gravity has less effect on you. For this reason, you actually weigh less at higher altitudes. A person who weighs 55kg can use this function to find out their weight: [6400(55)]/(h+6400), at a specific height (h) above sea evel.
Find the instantaneous rate of change at 12000 ft above sea level.
How my teacher told me to do it:
[w(12000.001w(1199.999)]/0.002 = 0.00609
Whatever happened to using LIMITS ?
 one year ago
 one year ago
pottersheep Group Title
I'm confused about rates of change? Why don't I put this into the limit formula? (Grade 12 Adv Functions) Question: As you get father from the earth's surface, gravity has less effect on you. For this reason, you actually weigh less at higher altitudes. A person who weighs 55kg can use this function to find out their weight: [6400(55)]/(h+6400), at a specific height (h) above sea evel. Find the instantaneous rate of change at 12000 ft above sea level. How my teacher told me to do it: [w(12000.001w(1199.999)]/0.002 = 0.00609 Whatever happened to using LIMITS ?
 one year ago
 one year ago

This Question is Closed

jefftheloveableguy Group TitleBest ResponseYou've already chosen the best response.1
This Newton's law of universal gravitation i think. Well i guess when taking a limit all you need to do is directly plug in the value into h. This would be the limit as h approached 12000 feet?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Isnt this like a "cheat" way to do limits? What happened to properly using the formula?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
He's not giving you the instantaneous rate of change then, hes giving you the average rate of change over a small interval. If you wanna do a limit you can.
 one year ago

jefftheloveableguy Group TitleBest ResponseYou've already chosen the best response.1
Right i guess so. What he is doing is dw/d(something i dont know) so dw would be a differential and i dont know what the 0.002 is. By the way are you in 12th grade AP physics?
 one year ago

jefftheloveableguy Group TitleBest ResponseYou've already chosen the best response.1
the d of something i dont know would not be the 55 kg because that stays constant
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Thanks guys
 one year ago
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